zoukankan      html  css  js  c++  java
  • A. Anton and Letters

    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.

    Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.

    Input

    The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.

    Output

    Print a single number — the number of distinct letters in Anton's set.

    Sample test(s)
    input
    {a, b, c}
    
    output
    3
    
    input
    {b, a, b, a}
    
    output
    2
    
    input
    {}
    
    output
    0

    解题说明:此题事实上就是考察C++中的set,把输入处理好就可以。

    #include<iostream>
    #include<cstdio>
    #include<cmath>
    #include<algorithm>
    #include<cstdlib>
    #include<cstring>
    #include <set>
    using namespace std;
    
    int main()
    {
    	string s;
    	set<char> t;
    	while (cin>>s)
    	{
    		if (s[0]!='{') 
    		{
    			t.insert(s[0]);
    		}
    		else if (s[1]!='}')
    		{
    			t.insert(s[1]);
    		}
    	}
    	cout<<t.size()<<endl;
    	return 0;
    }
    


  • 相关阅读:
    公司上线流程 pushonline_alpha
    关于统计数据
    实习生新手指南1
    菜鸟代码学习散点总结(四)
    菜鸟机器学习散点总结(三)
    菜鸟机器学习散点总结(二)
    springboot 中事件监听模型的一种实现
    java 代码获取视频时长
    spring cloud 服务链路追踪 skywalking 6.1
    windows 中如何定位恶意软件的藏身位置
  • 原文地址:https://www.cnblogs.com/yxwkf/p/3916167.html
Copyright © 2011-2022 走看看