经典的BFS路长为一求最短路
思路:
先找钥匙 再找箱子
两次BFS
未找到钥匙不可走箱子
先把箱子变墙
找到钥匙再恢复
注意判重
//#pragma GCC optimize(2)
#include <cstdio>
#include <iostream>
#include <cstdlib>
#include <cmath>
#include <cctype>
#include <string>
#include <cstring>
#include <algorithm>
#include <stack>
#include <queue>
#include <set>
#include <map>
#include <ctime>
#include <vector>
#include <fstream>
#include <list>
#include <iomanip>
#include <numeric>
using namespace std;
typedef long long ll;
const int MAXN = 1010;
char arr[1010][1010];
int usea[MAXN][MAXN] = {0}, useb[MAXN][MAXN] = {0};
ll n, m, ra, rb, ansa = 0, ansb = 0 , ta, tb;
bool finda = false, findb = false;
struct node
{
int x, y, step;
node(int xa, int ya, int za)
{
x = xa;
y = ya;
step = za;
}
};
int movel[4][2] = { {1, 0}, {0, 1}, {-1, 0}, {0, -1} };
queue <node> Q;
queue <node> QB;
void bfs(node a)
{
Q.push(a);
while(!Q.empty())
{
node b = Q.front();
Q.pop();
if( !(b.x < 1 || b.x > n || b.y < 1 || b.y > m || arr[b.x][b.y] == '*' || usea[b.x][b.y] == 1) )
{
usea[b.x][b.y] = 1;
if(arr[b.x][b.y] == 'S')
{
finda = true;
ansa = b.step;
return ;
}
for(int i = 0; i < 4; i++)
{
Q.push(node(b.x + movel[i][0], b.y + movel[i][1], b.step + 1));
}
}
}
}
void bfsb(node a)
{
QB.push(a);
while(!QB.empty())
{
node b = QB.front();
QB.pop();
if( !(b.x < 1 || b.x > n || b.y < 1 || b.y > m || arr[b.x][b.y] == '*' || useb[b.x][b.y] == 1) )
{
useb[b.x][b.y] = 1;
if(arr[b.x][b.y] == 'T')
{
findb = true;
ansb = b.step;
return ;
}
for(int i = 0; i < 4; i++)
{
QB.push(node(b.x + movel[i][0], b.y + movel[i][1], b.step + 1));
}
}
}
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0); cout.tie(0);
cin>>n>>m;
for(int i = 1; i <= n; i++)
{
for(int j = 1; j <= m; j++)
{
cin>>arr[i][j];
if(arr[i][j] == 'T')
{
arr[i][j] = '*';
ra = i;
rb = j;
}
if(arr[i][j] == 'S')
{
ta = i;
tb = j;
}
}
}
int x, y;
cin>>x>>y;
node in(x, y, 0);
bfs(in);
arr[ra][rb] = 'T';
if(finda)
{
node in(ta, tb, 0);
bfsb(in);
}
if(finda && findb)
cout<<ansa + ansb<<endl;
else
cout<<"-1"<<endl;
return 0;
}