Codeforces Round #FF (Div. 1)——A贪心——DZY Loves Sequences

DZY has a sequence a, consisting of n integers.

We'll call a sequence ai, ai + 1, ..., aj (1 ≤ i ≤ j ≤ n) a subsegment of the sequence a. The value (j - i + 1) denotes the length of the subsegment.

Your task is to find the longest subsegment of a, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.

You only need to output the length of the subsegment you find.

Input

The first line contains integer n (1 ≤ n ≤ 105). The next line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 109).

Output

In a single line print the answer to the problem — the maximum length of the required subsegment.

Sample test(s)

input

6
7 2 3 1 5 6

output

5

Note

You can choose subsegment a2, a3, a4, a5, a6 and change its 3rd element (that is a4) to 4.

/*
    大意：改一个数，使得递增最长
    对每一个数求出L[i],R[i],枚举每一个i的改变，如果a[i+1] - a[i-1] >= 2的时候说明可以连在一起，特判搞a[1]，和a[n]的情况以及只有1个数的情况

*/
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
const int MAX = 110000;
long long  a[MAX];
int L[MAX], R[MAX];
int main()
{
    int n;
    while(~scanf("%d", &n)){
        memset(a, 0, sizeof(a));
        for(int i = 1; i <= n ;i++){
            scanf("%lld", &a[i]);
        }
        for(int i = 0 ; i <= MAX; i++)
            L[i] = R[i] = 1;
       for(int i = 2; i <= n; i++){
            if(a[i] > a[i-1])
                L[i] = L[i-1] + 1;
            else L[i] = 1;
        }
    //   for(int i = 1; i <= n ; i++)
    //      printf("%d ",L[i]);
        for(int i = n - 1; i >= 1; i--){
            if(a[i] < a[i+1])
                R[i] = R[i+1] + 1;
            else R[i] = 1;
        }
        
        int max1 = max(R[1], L[n]);
        if(n >=2 ) max1 = max(max1, max(R[2] + 1, L[n-1] + 1));
        int max2 = 0;
        for(int i = 2; i <= n - 1 ; i++){
            if(a[i+1] - a[i-1] >= 2) 
                max1 = max(R[i+1] + L[i-1] + 1, max1);
            max2 = max(R[i+1] + 1, L[i-1] + 1);
            max1 = max(max1, max2);
        }
        printf("%d
", max1);
    }
    return 0;
}