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  • HDU5312——数学——Sequence(未完成)

    Today, Soda has learned a sequence whose n-th (n1) item is 3n(n1)+1. Now he wants to know if an integer m can be represented as the sum of some items of that sequence. If possible, what are the minimum items needed?

    For example, 22=19+1+1+1=7+7+7+1.

     


    Input
    There are multiple test cases. The first line of input contains an integer T (1T104), indicating the number of test cases. For each test case:

    There's a line containing an integer m (1m109).
     


    Output
    For each test case, output 1 if m cannot be represented as the sum of some items of that sequence, otherwise output the minimum items needed.
     


    Sample Input
    10 1 2 3 4 5 6 7 8 22 10
     


    Sample Output
    1 2 3 4 5 6 1 2 4 4
     


    Source
    /*
    对于(n-1)%6 + 1还没想明白,等脑子清醒了再搞。。。
    
    */
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    
    const int MAX = 20000;
    int a[MAX];
    void solve()
    {
        for(int i = 0; i <= MAX; i++)
            a[i] = 3 * i * (i-1) + 1;
    }
    int solve(int n)
    {
        int ans = n % 6;
        if(ans == 1){
            for(int i = 0 ; i <= MAX; i++){
                if(a[i] == n) return 1;
            }
            return 7;
        }
        if(ans == 2){
            int j = MAX - 1;
            for(int i = 1; i <=j; i++){
                while(a[i] + a[j] > n)
                    j--;
                if(a[i] + a[j] == n)
                    return 2;
            }
            return 8;
        }
        return (n - 1) % 6 + 1;
    }
    int main()
    {
        int T, n;
        scanf("%d", &T);
        while(T--){
        scanf("%d", &n);
        printf("%d
    ", solve(n));
        }
        return 0;
    }
        
    

      

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  • 原文地址:https://www.cnblogs.com/zero-begin/p/4678683.html
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