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  • codeforces 667A A. Pouring Rain(水题)

    题目链接:

    A. Pouring Rain

    time limit per test
    1 second
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, contemplate all around you, enjoy freshness, think about big deeds you have to do.

    Today everything had changed quietly. You went on the street with a cup contained water, your favorite drink. In a moment when you were drinking a water you noticed that the process became quite long: the cup still contained water because of rain. You decided to make a formal model of what was happening and to find if it was possible to drink all water in that situation.

    Thus, your cup is a cylinder with diameter equals d centimeters. Initial level of water in cup equals h centimeters from the bottom.

    You drink a water with a speed equals v milliliters per second. But rain goes with such speed that if you do not drink a water from the cup, the level of water increases on e centimeters per second. The process of drinking water from the cup and the addition of rain to the cup goes evenly and continuously.

    Find the time needed to make the cup empty or find that it will never happen. It is guaranteed that if it is possible to drink all water, it will happen not later than after 104 seconds.

    Note one milliliter equals to one cubic centimeter.

    Input
     

    The only line of the input contains four integer numbers d, h, v, e (1 ≤ d, h, v, e ≤ 104), where:

    • d — the diameter of your cylindrical cup,
    • h — the initial level of water in the cup,
    • v — the speed of drinking process from the cup in milliliters per second,
    • e — the growth of water because of rain if you do not drink from the cup.
    Output
     

    If it is impossible to make the cup empty, print "NO" (without quotes).

    Otherwise print "YES" (without quotes) in the first line. In the second line print a real number — time in seconds needed the cup will be empty. The answer will be considered correct if its relative or absolute error doesn't exceed 10 - 4. It is guaranteed that if the answer exists, it doesn't exceed 104.

    Examples
    input
    1 2 3 100
    output
    NO
    input
    1 1 1 1
    output
    YES
    3.659792366325
    Note

    In the first example the water fills the cup faster than you can drink from it.

    In the second example area of the cup's bottom equals to , thus we can conclude that you decrease the level of water by centimeters per second. At the same time water level increases by 1 centimeter per second due to rain. Thus, cup will be empty in  seconds.

    题意

    问杯子里的水能否被喝完,在喝水的时候还会加水;

    思路

    如果加水的速度大于等于喝水的速度,就喝不完,否则就可以算出喝完的时间了;

    AC代码

    #include <bits/stdc++.h>
    using namespace std;
    typedef long long LL;
    const LL mod=1e9+7;
    const int N=1e5+6;
    const int inf=0x3f3f3f3f;
    const double PI=acos(-1.0);
    int main()
    {
        double d,h,v,e;
        cin>>d>>h>>v>>e;
        d=d/2;
        double ans=(PI*d*d*h)/(v-PI*d*d*e);
        if(PI*d*d*e>v)cout<<"NO"<<"
    ";
        else
        {
            cout<<"YES"<<"
    ";
            printf("%.10lf",ans);
        }
    
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zhangchengc919/p/5451472.html
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