zoukankan      html  css  js  c++  java
  • codeforces 701A A. Cards(水题)

    题目链接:

    A. Cards

    题意:

    问两个数的和相同,怎么组合;

     

    AC代码:

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #include <bits/stdc++.h>
    #include <stack>
    
    using namespace std;
    
    #define For(i,j,n) for(int i=j;i<=n;i++)
    #define mst(ss,b) memset(ss,b,sizeof(ss));
    
    typedef  long long LL;
    
    template<class T> void read(T&num) {
        char CH; bool F=false;
        for(CH=getchar();CH<'0'||CH>'9';F= CH=='-',CH=getchar());
        for(num=0;CH>='0'&&CH<='9';num=num*10+CH-'0',CH=getchar());
        F && (num=-num);
    }
    int stk[70], tp;
    template<class T> inline void print(T p) {
        if(!p) { puts("0"); return; }
        while(p) stk[++ tp] = p%10, p/=10;
        while(tp) putchar(stk[tp--] + '0');
        putchar('
    ');
    }
    
    const LL mod=1e9+7;
    const double PI=acos(-1.0);
    const int inf=1e9;
    const int N=1e5+10;
    const int maxn=500+10;
    const double eps=1e-6;
    
    int n,a[200],vis[200];
    
    int main()
    {       
            int n;
            read(n);
            int sum=0;
            For(i,1,n)read(a[i]),sum+=a[i];
            int le=2*sum/n;
            For(i,1,n)   
            {
                if(vis[i])continue;
                For(j,1,n)
                {
                    if(!vis[j]&&a[i]+a[j]==le&&i!=j)
                    {
                        cout<<i<<" "<<j<<endl;
                        vis[i]=1;
                        vis[j]=1;
                        break;
                    }
                }
            }  
            return 0;
    }
    

      

     

  • 相关阅读:
    for memory long term update
    Tomcat 部署 Jenkins (Linux系统)
    Linux新增硬盘
    jenkins常见问题
    Linux安装JDk
    Jenkins入门(一)
    主播必备工具Bongo Cat!
    Docker常用命令
    Docker二进制部署
    golang中for语句详解
  • 原文地址:https://www.cnblogs.com/zhangchengc919/p/5698374.html
Copyright © 2011-2022 走看看