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  • dispatch_sync死锁问题

    首先,看看如下代码的输出是什么?

    - (void)viewDidLoad {
        [super viewDidLoad];
        NSLog(@"Hello");
                dispatch_sync(dispatch_get_main_queue(), ^{
                    NSLog(@"World");
                });
    }

    首先答案是会发生死锁,我们看看官方文档关于dispatch_sync的解释:

    Submits a block to a dispatch queue like dispatch_async(), however
    dispatch_sync() will not return until the block has finished.

    Calls to dispatch_sync() targeting the current queue will result
    in dead-lock. Use of dispatch_sync() is also subject to the same
    multi-party dead-lock problems that may result from the use of a mutex
    .
    Use of dispatch_async() is preferred.

    Unlike dispatch_async(), no retain is performed on the target queue. Because
    calls to this function are synchronous, the dispatch_sync() "borrows" the
    reference of the caller.

    As an optimization, dispatch_sync() invokes the block on the current
    thread when possible.

    如果dispatch_sync()的目标queue为当前queue,会发生死锁(并行queue并不会)。使用dispatch_sync()会遇到跟我们在pthread中使用mutex锁一样的死锁问题。

    话是这么说,我们看看究竟是怎么做的?先放码:

    source/queue.c

    void
    dispatch_sync(dispatch_queue_t dq, void (^work)(void))
    {
        struct Block_basic *bb = (void *)work;
        dispatch_sync_f(dq, work, (dispatch_function_t)bb->Block_invoke);
    }
    
    DISPATCH_NOINLINE
    void
    dispatch_sync_f(dispatch_queue_t dq, void *ctxt, dispatch_function_t func)
    {
        typeof(dq->dq_running) prev_cnt;
        dispatch_queue_t old_dq;
    
        if (dq->dq_width == 1) {
            return dispatch_barrier_sync_f(dq, ctxt, func);
        }
    
        // 1) ensure that this thread hasn't enqueued anything ahead of this call
        // 2) the queue is not suspended
        if (slowpath(dq->dq_items_tail) || slowpath(DISPATCH_OBJECT_SUSPENDED(dq))) {
            _dispatch_sync_f_slow(dq);
        } else {
            prev_cnt = dispatch_atomic_add(&dq->dq_running, 2) - 2;
    
            if (slowpath(prev_cnt & 1)) {
                if (dispatch_atomic_sub(&dq->dq_running, 2) == 0) {
                    _dispatch_wakeup(dq);
                }
                _dispatch_sync_f_slow(dq);
            }
        }
    
        old_dq = _dispatch_thread_getspecific(dispatch_queue_key);
        _dispatch_thread_setspecific(dispatch_queue_key, dq);
        func(ctxt);
        _dispatch_workitem_inc();
        _dispatch_thread_setspecific(dispatch_queue_key, old_dq);
    
        if (slowpath(dispatch_atomic_sub(&dq->dq_running, 2) == 0)) {
            _dispatch_wakeup(dq);
        }
    }

    Step1. 可以看到dispatch_sync将我们block函数指针进行了一些转换后,直接传给了dispatch_sync_f()去处理。

    Step2. dispatch_sync_f首先检查传入的队列宽度(dq_width),由于我们传入的main queue为串行队列,队列宽度为1,所有接下来会调用dispatch_barrier_sync_f,传入3个参数,dispatch_sync中的目标queue、上下文信息和由我们block函数指针转化过后的func结构体。

    接下来我们看看dispatch_barrier_sync_f的实现

    source/queue.c

    void
    dispatch_barrier_sync_f(dispatch_queue_t dq, void *ctxt, dispatch_function_t func)
    {
        dispatch_queue_t old_dq = _dispatch_thread_getspecific(dispatch_queue_key);
    
        // 1) ensure that this thread hasn't enqueued anything ahead of this call
        // 2) the queue is not suspended
        // 3) the queue is not weird
        if (slowpath(dq->dq_items_tail)
                || slowpath(DISPATCH_OBJECT_SUSPENDED(dq))
                || slowpath(!_dispatch_queue_trylock(dq))) {
            return _dispatch_barrier_sync_f_slow(dq, ctxt, func);
        }
    
        _dispatch_thread_setspecific(dispatch_queue_key, dq);
        func(ctxt);
        _dispatch_workitem_inc();
        _dispatch_thread_setspecific(dispatch_queue_key, old_dq);
        _dispatch_queue_unlock(dq);
    }

    Step3. disptach_barrier_sync_f首先做了做了3个判断:

    • 队列存在尾部节点状态(判断当前是不是处于队列尾部)
    • 队列不为暂停状态
    • 使用_dispatch_queue_trylock检查队列能被正常加锁。

    满足所有条件则不执行if语句内的内容,执行下面代码,简单解释为:

    • 使用mutex锁,获取到当前进程资源锁。
    • 直接执行我们block函数指针的具体内容。
    • 然后释放锁,整个调用结束。

    然后在我们例子中,很显然当前队列中还有其他viewController的任务,我们的流程跑到_dispatch_barrier_aync_f_slow()函数体中。

    刨根问底,让我们看看这个函数。

    source/queue.c

    static void
    _dispatch_barrier_sync_f_slow(dispatch_queue_t dq, void *ctxt, dispatch_function_t func)
    {
    
        // It's preferred to execute synchronous blocks on the current thread
        // due to thread-local side effects, garbage collection, etc. However,
        // blocks submitted to the main thread MUST be run on the main thread
    
        struct dispatch_barrier_sync_slow2_s dbss2 = {
            .dbss2_dq = dq,
    #if DISPATCH_COCOA_COMPAT
            .dbss2_func = func,
            .dbss2_ctxt = ctxt,
    #endif
            .dbss2_sema = _dispatch_get_thread_semaphore(),
        };
        struct dispatch_barrier_sync_slow_s {
            DISPATCH_CONTINUATION_HEADER(dispatch_barrier_sync_slow_s);
        } dbss = {
            .do_vtable = (void *)DISPATCH_OBJ_BARRIER_BIT,
            .dc_func = _dispatch_barrier_sync_f_slow_invoke,
            .dc_ctxt = &dbss2,
        };
    //---------------重点是这里---------------    
        _dispatch_queue_push(dq, (void *)&dbss);
        dispatch_semaphore_wait(dbss2.dbss2_sema, DISPATCH_TIME_FOREVER);
        _dispatch_put_thread_semaphore(dbss2.dbss2_sema);
    
    #if DISPATCH_COCOA_COMPAT
        // Main queue bound to main thread
        if (dbss2.dbss2_func == NULL) {
            return;
        }
    #endif
        dispatch_queue_t old_dq = _dispatch_thread_getspecific(dispatch_queue_key);
        _dispatch_thread_setspecific(dispatch_queue_key, dq);
        func(ctxt);
        _dispatch_workitem_inc();
        _dispatch_thread_setspecific(dispatch_queue_key, old_dq);
        dispatch_resume(dq);
    }

    Step4. 既然我们上面已经判断了,main queue中还有其他任务,现在不能直接执行这个block,跳入到_dispatch_barrier_sync_f_slow函数体,那它怎么处理我们加入的block呢?

    在_dispatch_barrier_sync_f_slow中,使用_dispatch_queue_push将我们的block压入main queue的FIFO队列中,然后等待信号量,ready后被唤醒。

    然后dispatch_semaphore_wait返回_dispatch_semaphore_wait_slow(dsema, timeout)函数,持续轮训并等待,直到条件满足。

    所以在此过程中,我们最初调用的dispatch_sync函数一直得不到返回,main queue被阻塞,而我们的block又需要等待main queue来执行它。死锁愉快的产生了。

    最后:

    我们绘制上张图来轻松的描述一下这个问题:


     
    转http://www.jianshu.com/p/44369c02b62a
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  • 原文地址:https://www.cnblogs.com/zhangleixy/p/5130541.html
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