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  • 大转盘抽奖概率 固定每个区域的中奖几率


    get_double_reward_index 完整算法复制运用即可
    原理一共是100份落到每一份概率相等,循环次数越多抽奖越是准确
    def get_double_reward_index(rate_conf):
        """
        抽奖概率计算
        rate_conf = [[0.25, ''], [0.05, 129600], [0.01, 777600], [0.35, ''], [0.2, ''], [0.14, 10]]
        return 奖励index
        """
        start, index = 0, 0
        rate = [i[0] for i in rate_conf]
        randnum = random.uniform(0, sum(rate))
        for index, scope in enumerate(rate):
            start += scope
            if randnum <= start:
                break
        return index
    
    
    
        l1 = [[0.25, ''], [0.05, 129600], [0.01, 777600], [0.35, ''], [0.2, ''], [0.14, 10]]
        c = get_double_reward_index(l1)
    
        total, i0, i1, i2, i3, i4, i5 = 0, 0, 0, 0, 0, 0, 0
        for i in range(1000000):
            index = get_double_reward_index(rate_conf=l1)
            total += 1
            if index == 0:
                i0 += 1
            elif index == 1:
                i1 += 1
            elif index == 2:
                i2 += 1
            elif index == 3:
                i3 += 1
            elif index == 4:
                i4 += 1
            elif index == 5:
                i5 += 1
    
        print("index 0 概率 %f" % ((i0 / total) * 100))
        print("index 1 概率 %f" % ((i1 / total) * 100))
        print("index 2 概率 %f" % ((i2 / total) * 100))
        print("index 3 概率 %f" % ((i3 / total) * 100))
        print("index 4 概率 %f" % ((i4 / total) * 100))
        print("index 5 概率 %f" % ((i5 / total) * 100))
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  • 原文地址:https://www.cnblogs.com/zhaoyingjie/p/11661509.html
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