Question
There are N gas stations along a circular route, where the amount of gas at station i isgas[i].
You have a car with an unlimited gas tank and it costscost[i]of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.
Note:
The solution is guaranteed to be unique.
Solution
这道题采用贪心的思想,如果这站到下一站不能满足要求的话,就从下一站开始,然后记录已经走过的地方所缺的油量的数目。
Code
class Solution {
public:
int canCompleteCircuit(vector<int> &gas, vector<int> &cost) {
int tankCount = 0;
int need = 0;
int start = 0;
for (int i = 0; i < gas.size(); i++) {
tankCount += gas[i];
if (tankCount >= cost[i]) {
tankCount -= cost[i];
need -= (gas[i] - cost[i]);
} else {
need += (cost[i] - gas[i]);
tankCount = 0;
start = i + 1;
}
}
if (tankCount >= need)
return start;
else
return -1;
}
};