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  • 【LeetCode】4.Median of Two Sorted Arrays 两个有序数组中位数

    题目:

      There are two sorted arrays nums1 and nums2 of size m and n respectively.

      Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).

    Example 1:

     nums1 = [1, 3]
     nums2 = [2]
    
     The median is 2.0

    Example 2:

     nums1 = [1, 2]
     nums2 = [3, 4]
    
     The median is (2 + 3)/2 = 2.5
    public class Solution {
        public double findMedianSortedArrays(int[] nums1, int[] nums2) {
            int len1=nums1.length;
            int len2=nums2.length;
            int k=len1+len2;
            
            if(k%2!=0){
               return findMedian(nums1,0,len1,nums2,0,len2,k/2+1);
            }else{
                return (findMedian(nums1,0,len1,nums2,0,len2,k/2)+findMedian(nums1,0,len1,nums2,0,len2,k/2+1))/2;
            }
        }
        public static double findMedian(int[] nums1,int start1,int end1,int[] nums2,int start2,int end2,int k ){
            if(end1>end2){
                return findMedian(nums2,start2,end2,nums1,start1,end1,k);
            }
            
            if(end1<=0){
                return nums2[start2+k-1];
            }
            
            if(k==1){
                return Math.min(nums1[start1],nums2[start2]);
            }
            
            int k1=Math.min(k/2,end1);
            int k2=k-k1;
            if(nums1[start1+k1-1]<nums2[start2+k2-1]){
                return findMedian(nums1,start1+k1,end1-k1,nums2,start2,end2,k-k1);
            }else{
                return findMedian(nums1,start1,end1,nums2,start2+k2,end2-k2,k-k2);
            }
        }
    }
    

      

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  • 原文地址:https://www.cnblogs.com/zhstudy/p/5988306.html
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