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求一个数组的最大子数组之和03

这次求二维数组的最大子连通数组：

这次的要求有点偏难在好多同学的指导下才完成此任务

  1 #include<iostream>
  2 using namespace std;
  3 
  4 struct point
  5 {
  6     int x, y;
  7 };
  8 
  9 int add(int a[5][5], int i, int j, int k)
 10 {
 11     int n;
 12     int b = 0;
 13     for (n = j; n <= i + j; n++)
 14     {
 15         b += a[n][k];
 16     }
 17     return b;
 18 }
 19 
 20 void main ()
 21 {
 22         int x=5,y=5,i, j, k, l;
 23         int sum = 0, s, h, e;
 24         point head;
 25         point end;
 26         int a[5][5];
 27         int b[5];
 28         cout << "请输入数组中的数：" << endl;
 29         for (i = 0; i<x; i++)
 30         {
 31             for (j = 0; j<y; j++)
 32             {
 33                 cin>>a[i][j];
 34             }
 35         }
 36         for (i = 0; i<x; i++)
 37         {
 38             for (j = 0; i + j<x; j++)
 39             {
 40                 s = 0;
 41                 h = 0;
 42                 e = 0;
 43                 for (k = 0; k<y; k++)
 44                 {
 45                     b[k] = add(a, i, j, k);
 46 
 47                 }
 48 
 49                 for (l = 0; l<x; l++)
 50 
 51                 {
 52 
 53                     s += b[l];
 54 
 55                     if (s>0)
 56 
 57                     {
 58 
 59                         e++;
 60 
 61                     }
 62 
 63                     else
 64 
 65                     {
 66 
 67                         s = 0;
 68 
 69                         h = l + 1;
 70 
 71                         e++;
 72 
 73                     }
 74 
 75                     if (s>sum)
 76 
 77                     {
 78 
 79                         sum = s;
 80 
 81                         head.x = h;
 82 
 83                         head.y = j;
 84 
 85                         end.x = e;
 86 
 87                         end.y = i + j;
 88 
 89                     }
 90 
 91                 }
 92 
 93                 if (s>0 && h != 0)
 94 
 95                 {
 96 
 97                     l = 0;
 98 
 99                     e = e - x;
100 
101                     while (s>0 && e != h - 1)
102 
103                     {
104 
105                         s += b[l];
106 
107                         l++;
108 
109                         e++;
110 
111                         if (s>sum)
112 
113                         {
114 
115                             sum = s;
116 
117                             head.x = h;
118 
119                             head.y = j;
120 
121                             end.x = e;
122 
123                             end.y = i + j;
124 
125                         }
126 
127                     }
128 
129                 }
130 
131             }
132 
133         }
134         cout<<"最大子数组的和为:"<<sum<<endl;
135         cout<<"最大子数组为:"<<endl;
136         if (end.x>head.x)
137         {
138             for (i = head.y; i <= end.y; i++)
139             {
140                 for (j = head.x; j<end.x; j++)
141                 {
142                     cout<<a[i][j]<<" ";
143                 }
144                 cout << endl;
145             }
146         }
147         else
148         {
149             for (i = head.y; i <= end.y; i++)
150             {
151                 for (j = head.x; j < x; j++)
152                 {
153                     cout << a[i][j] << " ";
154                 }
155                 for (j = 0; j < end.x; j++)
156                 {
157                     cout << a[i][j] << " ";
158                 }
159                 cout << endl;
160             }
161         }
162         system("pause");
163 }

合作人：靳琪

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原文地址：https://www.cnblogs.com/zjy666/p/5360226.html