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  • 1050 String Subtraction (20 分)

    1050 String Subtraction (20 分)
     

    Given two strings S1​​ and S2​​, S=S1​​S2​​ is defined to be the remaining string after taking all the characters in S2​​ from S1​​. Your task is simply to calculate S1​​S2​​ for any given strings. However, it might not be that simple to do it fast.

    Input Specification:

    Each input file contains one test case. Each case consists of two lines which gives S1​​ and S2​​, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

    Output Specification:

    For each test case, print S1​​S2​​ in one line.

    Sample Input:

    They are students.
    aeiou
    

    Sample Output:

    Thy r stdnts.

    送分题就不多说了。

     1 #include <bits/stdc++.h>
     2 
     3 using namespace std;
     4 string s, ss;
     5 int vis[500];
     6 int main(){
     7     getline(cin, s);
     8     getline(cin, ss);
     9     for(int i = 0; i < ss.length(); i++)
    10         vis[ss[i]] = 1;
    11     for(int i = 0; i < s.length(); i++)
    12         if(!vis[s[i]]){
    13             cout <<s[i];
    14         }
    15     cout << endl;
    16 
    17     return 0;
    18 }


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  • 原文地址:https://www.cnblogs.com/zllwxm123/p/11185316.html
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