#Leetcode# 151. Reverse Words in a String

https://leetcode.com/problems/reverse-words-in-a-string/

Given an input string, reverse the string word by word.

Example:  

Input: "the sky is blue",
Output: "blue is sky the".

Note:

• A word is defined as a sequence of non-space characters.
• Input string may contain leading or trailing spaces. However, your reversed string should not contain leading or trailing spaces.
• You need to reduce multiple spaces between two words to a single space in the reversed string.

代码：

class Solution {
public:
    void reverseWords(string &s) {
        int len = s.length();
        int newlen = 0;
        reverse(s.begin(), s.end());
        for(int i = 0; i < len; i ++) {
            if(s[i] != ' ') {
                if(newlen != 0) s[newlen ++] = ' ';
                int temp = i;
                while(temp < len && s[temp] != ' ')
                    s[newlen ++] = s[temp ++];
                
                reverse(s.begin() + newlen - (temp - i), s.begin() + newlen);
                
                i = temp;
            }
        }
        s.resize(newlen);
    }
};

$char$ 代码：

#include <bits/stdc++.h>
using namespace std;

char s[1010];
char ans[1010][30];

int main() {
    cin.getline(s, 1010);
    int len = strlen(s);
    s[len] = ' ';
    len ++;
    s[len] = '';

    int cnt = 0;
    for(int i = 0; i < len; i ++) {
        if(s[i] != ' ')
        for(int j = i; j < len; j ++) {
            if(s[j] != ' ') continue;
            else {
                cnt ++;
                for(int k = i; k < j; k ++)
                    ans[cnt][k - i] = s[k];

                i = j;
                break;
            }
        }
    }

    for(int i = 1; i <= cnt; i ++)
        cout << ans[i] << endl;
    return 0;
}

　　很神奇诶 以前只写过 $char$ 的反转 讲真 $string$ 是真的不怎么会 这道题是先整个反转 然后找到每个单词再反转 $newlen$ 记录新的长度 然后最后重新给 $s$ 分配一个大小为 $newlen$ 的空间 今天依旧是有点菜的一天哦