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  • PAT (Advanced Level) 1017. Queueing at Bank (25)

    简单模拟。

    #include<iostream>
    #include<cstring>
    #include<cmath>
    #include<algorithm>
    #include<cstdio>
    #include<map>
    #include<queue>
    using namespace std;
    
    struct X
    {
        long long hh,mm,ss;
        long long len;
        long long st,ml;
    }s[10000+10];
    int n,k;
    long long win[200];
    
    bool cmp(const X&a,const X&b)
    {
        return a.st<b.st;
    }
    
    int main()
    {
        scanf("%d%d",&n,&k);
        for(int i=1;i<=n;i++)
        {
            scanf("%lld:%lld:%lld %lld",&s[i].hh,&s[i].mm,&s[i].ss,&s[i].len);
            s[i].st=s[i].hh*60*60+s[i].mm*60+s[i].ss;
            s[i].len=s[i].len*60;
        }
        sort(s+1,s+1+n,cmp);
        for(int i=1;i<=k;i++) win[i]=8*60*60;
        int i;
        int cnt=0;
        for(int i=1;i<=n;i++)
        {
            long long Min=999999999999;
            if(s[i].st>17*60*60) break;
            cnt++;
            for(int j=1;j<=k;j++) Min=min(Min,win[j]);
            for(int j=1;j<=k;j++)
            {
                if(win[j]==Min)
                {
                    s[i].ml=max(win[j],s[i].st);
                    win[j]=s[i].ml+s[i].len;
                    break;
                }
            }
        }
        long long sum=0;
        for(int k=1;k<=cnt;k++) sum=sum+s[k].ml-s[k].st;
        if(cnt!=0) printf("%.1f
    ",1.0*sum/60/cnt);
        else printf("0.0
    ");
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zufezzt/p/5497723.html
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