gulp 4.0 提示 Error: watching index.html: watch task has to be a function 解决办法

gulp 4.0 提示 Error: watching index.html: watch task has to be a function 解决办法

 

原文链接：https://blog.csdn.net/mlonly/article/details/85917261

提示：Error: watching index.html: watch task has to be a function (optionally generated by using gulp.parallel or gulp.series)

gulp 4.0之后不能按照之前的写法了  大有改变

4.0之前的写法

Gulp.watch(“监听的文件”，[任务名字符串])

1.  
   // gulp.task("watch",function(){
2.  
   // gulp.watch("index.html",["copyindex"]);
3.  
   // gulp.watch("js/**/*",["copyjs"]);
4.  
   // gulp.watch("css/**/*.scss",["copycss"]);
5.  
   // gulp.watch("html/**/*",["copyhtml"]);
6.  
   // gulp.watch("php/**/*",["copyphp"]);
7.  
   // gulp.watch("img/**/*",["copyimg"]);
8.  
   // })

4.0之后的写法

Gulp.watch(“监听的文件”，回调函数)。

gulp.task("watch-all",async ()=>{

gulp.watch("index.html",async ()=>{
gulp.src("index.html")
.pipe(gulp.dest("D:\myphp_www\PHPTutorial\WWW\baidu"));
});
gulp.watch("js/**/*",async ()=>{
gulp.src("js/**/*")
.pipe(gulp.dest("D:\myphp_www\PHPTutorial\WWW\baidu\js"));
});
gulp.watch("css/**/*.scss",async ()=>{
gulp.src("css/**/*.scss")
.pipe(sass())
.pipe(gulp.dest("D:\myphp_www\PHPTutorial\WWW\baidu\css"));
});
gulp.watch("html/**/*",async ()=>{
gulp.src("html/**/*")
.pipe(gulp.dest("D:\myphp_www\PHPTutorial\WWW\baidu\html"));
});
gulp.watch("php/**/*",async ()=>{
gulp.src("php/**/*")
.pipe(gulp.dest("D:\myphp_www\PHPTutorial\WWW\baidu\php"));
});
gulp.watch("img/**/*",async ()=>{
gulp.src("img/**/*")
.pipe(gulp.dest("D:\myphp_www\PHPTutorial\WWW\baidu\img"));

});

});