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  • PAT甲级——A1083 List Grades

    Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

    Input Specification:

    Each input file contains one test case. Each case is given in the following format:

    N
    name[1] ID[1] grade[1]
    name[2] ID[2] grade[2]
    ... ...
    name[N] ID[N] grade[N]
    grade1 grade2
    

    where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

    Output Specification:

    For each test case you should output the student records of which the grades are in the given interval [grade1grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.

    Sample Input 1:

    4
    Tom CS000001 59
    Joe Math990112 89
    Mike CS991301 100
    Mary EE990830 95
    60 100
    

    Sample Output 1:

    Mike CS991301
    Mary EE990830
    Joe Math990112
    

    Sample Input 2:

    2
    Jean AA980920 60
    Ann CS01 80
    90 95
    

    Sample Output 2:

    NONE
     1 #include <iostream>
     2 #include <string>
     3 #include <algorithm>
     4 using namespace std;
     5 struct Node
     6 {
     7     string name, id;
     8     int grade;
     9 };
    10 int main()
    11 {
    12     int N, grade1, grade2;
    13     cin >> N;
    14     Node* data = new Node[N];
    15     for (int i = 0; i < N; ++i)
    16         cin >> data[i].name >> data[i].id >> data[i].grade;
    17     cin >> grade1 >> grade2;
    18     sort(data, data + N, [](Node a, Node b) {return a.grade > b.grade; });
    19     int flag = 1;
    20     for (int i = 0; i < N; ++i)
    21     {
    22         if (data[i].grade < grade1)
    23             break;
    24         if (data[i].grade >= grade1 && data[i].grade <= grade2)
    25         {
    26             cout << data[i].name << " " << data[i].id << endl;
    27             flag = 0;
    28         }
    29     }
    30     if (flag == 1)
    31         cout << "NONE" << endl;
    32     delete[]data;
    33     return 0;
    34 }
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  • 原文地址:https://www.cnblogs.com/zzw1024/p/11336629.html
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