zoukankan      html  css  js  c++  java
  • 全排列

    Now our hero finds the door to the BEelzebub feng5166. He opens the door and finds feng5166 is about to kill our pretty Princess. But now the BEelzebub has to beat our hero first. feng5166 says, "I have three question for you, if you can work them out, I will release the Princess, or you will be my dinner, too." Ignatius says confidently, "OK, at last, I will save the Princess." 

    "Now I will show you the first problem." feng5166 says, "Given a sequence of number 1 to N, we define that 1,2,3...N-1,N is the smallest sequence among all the sequence which can be composed with number 1 to N(each number can be and should be use only once in this problem). So it's easy to see the second smallest sequence is 1,2,3...N,N-1. Now I will give you two numbers, N and M. You should tell me the Mth smallest sequence which is composed with number 1 to N. It's easy, isn't is? Hahahahaha......" 
    Can you help Ignatius to solve this problem? 
    InputThe input contains several test cases. Each test case consists of two numbers, N and M(1<=N<=1000, 1<=M<=10000). You may assume that there is always a sequence satisfied the BEelzebub's demand. The input is terminated by the end of file. 
    OutputFor each test case, you only have to output the sequence satisfied the BEelzebub's demand. When output a sequence, you should print a space between two numbers, but do not output any spaces after the last number. 
    Sample Input
    6 4
    11 8
    Sample Output
    1 2 3 5 6 4
    1 2 3 4 5 6 7 9 8 11 10

    利用STL里面的next_permutation()做这道题不要太简单。。

    #include<iostream>
    #include<algorithm>
    using namespace std;
    #define N 1005
    void permutation(int *a,int length,int end)
    {
        int count=0;
        sort(a,a+length);
        do
        {
            count++;
            if(count==end)
                {
                    for(int i=0;i<length;i++)
                        {
                            if(i==length-1)
                                cout<<a[i];
                            else
                                cout<<a[i]<<" ";
                        }
                    break;
                }
        }
        while(next_permutation(a,a+length));
    }
    int main()
    {
        int x,a[N],y;
        while(cin>>x>>y)
        {
            for(int i=0;i<x;i++)
                a[i]=i+1;
            permutation(a,x,y);
            cout<<endl;
        }
        return 0;
    }
    

      

  • 相关阅读:
    obs问题记录
    树莓派数字识别相关资料
    Focus Event
    跨浏览器的事件对象
    浅谈Javascript事件模拟
    浅谈Javascript鼠标和滚轮事件
    UI Events
    IE事件对象(The Internet Explorer Event Object)
    eclipse 调试nodejs 发生Failed to connect to standalone V8 VM错误的解决方案
    关于couldn't connect to server 127.0.0.1 shell/mongo.js:84 exception: connect failed 问题
  • 原文地址:https://www.cnblogs.com/zzzying/p/7202226.html
Copyright © 2011-2022 走看看