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  • LOJ-10109(欧拉回路)

    题目链接:传送门

    思路:

    就是简单的找欧拉回路,不过要注意dfs边时要将边的编号/2,不然会分不清那条边每被遍历。

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    using namespace std;
    const int maxn = 1e5+10;
    int head[maxn],vis[maxn],ver[maxn],next[maxn],id[maxn],tot;
    int ans[maxn],tt,du[maxn];
    int MAX(int x,int y)
    {
        return x>y?x:y;
    }
    void Init()
    {
        memset(vis,0,sizeof(vis));
        memset(head,0,sizeof(head));
        memset(du,0,sizeof(du));
        tot=0;tt=0;
    }
    void addedge(int u,int v,int w)
    {
        ver[++tot]=v;next[tot]=head[u];id[tot]=w;head[u]=tot;
    }
    void dfs(int u)
    {
        for(int i=head[u];i;i=next[i]){
            int v=ver[i];
            if(!vis[(i+1)>>1]){
                vis[(i+1)>>1]=1;
                dfs(v);
                ans[++tt]=id[i];
            }
        }
    }
    int main(void)
    {
        int n,m,x,y,z,i,j,ss;
        while(scanf("%d%d",&x,&y)&&(x+y)){
            Init();
            scanf("%d",&z);
            du[x]++;du[y]++;
            ss=x<y?x:y;
            n=MAX(x,y);m=1;
            addedge(x,y,z);addedge(y,x,z);
            while(scanf("%d%d",&x,&y)&&(x+y)){
                scanf("%d",&z);
                n=MAX(n,MAX(x,y));m++;
                du[x]++;du[y]++;
                addedge(x,y,z);addedge(y,x,z);
            }
            int fg=1;
            for(i=1;i<=n;i++)
            if(du[i]%2){
                fg=0;break;
            } 
            
            if(fg==0) printf("Round trip does not exist.
    ");
            else{
                dfs(ss);
                if(m!=tt) printf("Round trip does not exist.
    ");
                else{
                    for(i=tt;i>=2;i--) printf("%d ",ans[i]);
                    printf("%d
    ",ans[1]);
                }
            }
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/2018zxy/p/10375150.html
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