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  • Codeforces 845E Fire in the City 线段树

    Fire in the City

    二分答案, 用扫描先加线段树去check

    #include<bits/stdc++.h>
    #define LL long long
    #define LD long double
    #define ull unsigned long long
    #define fi first
    #define se second
    #define mk make_pair
    #define PLL pair<LL, LL>
    #define PLI pair<LL, int>
    #define PII pair<int, int>
    #define SZ(x) ((int)x.size())
    #define ALL(x) (x).begin(), (x).end()
    #define fio ios::sync_with_stdio(false); cin.tie(0);
    
    using namespace std;
    
    const int N = 2e5 + 7;
    const int inf = 0x3f3f3f3f;
    const LL INF = 0x3f3f3f3f3f3f3f3f;
    const int mod = 998244353;
    const double eps = 1e-8;
    const double PI = acos(-1);
    
    template<class T, class S> inline void add(T& a, S b) {a += b; if(a >= mod) a -= mod;}
    template<class T, class S> inline void sub(T& a, S b) {a -= b; if(a < 0) a += mod;}
    template<class T, class S> inline bool chkmax(T& a, S b) {return a < b ? a = b, true : false;}
    template<class T, class S> inline bool chkmin(T& a, S b) {return a > b ? a = b, true : false;}
    
    vector<int> oo, gg;
    
    int getPos(int x) {
        return lower_bound(ALL(oo), x) - oo.begin() + 1;
    }
    
    namespace SGT {
    #define lson l, mid, rt << 1
    #define rson mid + 1, r, rt << 1 | 1
        int a[N << 2], lazy[N << 2];
        inline void push(int rt) {
            if(lazy[rt]) {
                a[rt << 1] += lazy[rt];
                a[rt << 1 | 1] += lazy[rt];
                lazy[rt << 1] += lazy[rt];
                lazy[rt << 1 | 1] += lazy[rt];
                lazy[rt] = 0;
            }
        }
        void build(int l, int r, int rt) {
            a[rt] = lazy[rt] = 0;
            if(l == r) return;
            int mid = l + r >> 1;
            build(lson); build(rson);
        }
        void update(int L, int R, int v, int l, int r, int rt) {
            if(R < l || r < L) return;
            if(L <= l && r <= R) {
                a[rt] += v;
                lazy[rt] += v;
                return;
            }
            push(rt);
            int mid = l + r >> 1;
            update(L, R, v, lson);
            update(L, R, v, rson);
            a[rt] = min(a[rt << 1], a[rt << 1 | 1]);
        }
        int getMinId(int l, int r, int rt) {
            if(a[rt] > 0) return -1;
            if(l == r) return oo[l - 1];
            push(rt);
            int mid = l + r >> 1;
            if(a[rt << 1] == 0) return getMinId(lson);
            else return getMinId(rson);
        }
        int getMaxId(int l, int r, int rt) {
            if(a[rt] > 0) return -1;
            if(l == r) return oo[l] - 1;
            push(rt);
            int mid = l + r >> 1;
            if(a[rt << 1 | 1] == 0) return getMaxId(rson);
            else return getMaxId(lson);
        }
    }
    
    
    struct Point {
        Point(int x = 0, int y = 0) : x(x), y(y) {}
        int x, y;
    };
    
    struct Rec {
        Point a, b;
    };
    
    Rec mergeRec(const Rec& lhs, const Rec& rhs) {
        Rec ans;
        ans.a.x = max(lhs.a.x, rhs.a.x);
        ans.a.y = max(lhs.a.y, rhs.a.y);
        ans.b.x = min(lhs.b.x, rhs.b.x);
        ans.b.y = min(lhs.b.y, rhs.b.y);
        return ans;
    }
    inline bool ok(const Rec& r) {
        return r.a.x <= r.b.x && r.a.y <= r.b.y;
    }
    
    int n, m, k;
    Point a[N];
    vector<Rec> vc, tmp;
    
    inline void go(Rec& now, Point p, int T) {
        now = mergeRec(now, Rec{Point(p.x - T, p.y - T), Point(p.x + T, p.y + T)});
    }
    
    bool check(int T) {
        oo.clear(); gg.clear();
        gg.push_back(1); gg.push_back(m + 1);
        oo.push_back(1); oo.push_back(n + 1);
        for(int i = 1; i <= k; i++) {
            oo.push_back(max(1, a[i].x - T));
            oo.push_back(min(n + 1, a[i].x + T + 1));
            gg.push_back(max(1, a[i].y - T));
            gg.push_back(min(m + 1, a[i].y + T + 1));
        }
        sort(oo.begin(), oo.end());
        oo.erase(unique(ALL(oo)), oo.end());
        sort(gg.begin(), gg.end());
        gg.erase(unique(ALL(gg)), gg.end());
        SGT::build(1, SZ(oo) - 1, 1);
        Rec now = Rec{Point(1, 1), Point(n, m)};
        for(int i = 0; i < SZ(gg); i++) {
            if(i > 0) {
                int mnx = SGT::getMinId(1, SZ(oo) - 1, 1);
                int mxx = SGT::getMaxId(1, SZ(oo) - 1, 1);
                if(~mnx) {
                    go(now, Point(mnx, gg[i - 1]), T);
                    go(now, Point(mnx, gg[i] - 1), T);
                    go(now, Point(mxx, gg[i - 1]), T);
                    go(now, Point(mxx, gg[i] - 1), T);
                }
            }
            if(i == SZ(gg) - 1) break;
            for(int j = 1; j <= k; j++) {
                if(max(1, a[j].y - T) == gg[i]) {
                    SGT::update(getPos(max(1, a[j].x - T)), getPos(min(n + 1, a[j].x + T + 1)) - 1, 1, 1, SZ(oo) - 1, 1);
                }
                if(min(m + 1, a[j].y + T + 1) == gg[i]) {
                    SGT::update(getPos(max(1, a[j].x - T)), getPos(min(n + 1, a[j].x + T + 1)) - 1, -1, 1, SZ(oo) - 1, 1);
                }
            }
        }
        return ok(now);
    }
    
    int main() {
        scanf("%d%d%d", &n, &m, &k);
        for(int i = 1; i <= k; i++) scanf("%d%d", &a[i].x, &a[i].y);
        int low = 0, high = max(n, m), ans = high;
        while(low <= high) {
            int mid = low + high >> 1;
            if(check(mid)) high = mid - 1, ans = mid;
            else low = mid + 1;
        }
        printf("%d
    ", ans);
        return 0;
    }
    
    /*
    */
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  • 原文地址:https://www.cnblogs.com/CJLHY/p/10857611.html