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  • 【POJ】2778 DNA Sequence

      1 #include<cstdio>
      2 #include<cstring>
      3 #include<queue>
      4 typedef long long LL;
      5 #define MAXN 110
      6 #define MOD 100000
      7 using namespace std;
      8 char str[MAXN];
      9 int size;
     10 struct Matrix {
     11     LL mat[MAXN][MAXN];
     12     void Zero() {
     13         memset(mat, 0, sizeof(mat));
     14     }
     15     void Unit() {
     16         int i;
     17         for (i = 0; i <= size; i++)
     18             mat[i][i] = 1;
     19     }
     20 };
     21 struct Trie {
     22     int fail, next[4];
     23     bool end;
     24     void Init() {
     25         fail = 0;
     26         end = false;
     27         memset(next, 0, sizeof(next));
     28     }
     29 };
     30 Matrix a, b;
     31 Trie tree[MAXN];
     32 Matrix operator *(const Matrix &a, const Matrix &b) {
     33     Matrix temp;
     34     int i, j, k;
     35     temp.Zero();
     36     for (i = 0; i <= size; i++) {
     37         for (j = 0; j <= size; j++) {
     38             for (k = 0; k <= size; k++)
     39                 temp.mat[i][j] += a.mat[i][k] * b.mat[k][j];
     40             temp.mat[i][j] %= MOD;
     41         }
     42     }
     43     return temp;
     44 }
     45 inline int GET(char ch) {
     46     if (ch == 'A')
     47         return 0;
     48     if (ch == 'C')
     49         return 1;
     50     if (ch == 'G')
     51         return 2;
     52     return 3;
     53 }
     54 void Insert(char *s) {
     55     int now, t;
     56     for (now = 0; *s; s++) {
     57         t = GET(*s);
     58         if (!tree[now].next[t]) {
     59             tree[++size].Init();
     60             tree[now].next[t] = size;
     61         }
     62         now = tree[now].next[t];
     63     }
     64     tree[now].end = true;
     65 }
     66 void BFS() {
     67     int now, i, p;
     68     queue<int> q;
     69     q.push(0);
     70     while (!q.empty()) {
     71         now = q.front();
     72         q.pop();
     73         for (i = 0; i < 4; i++) {
     74             if (tree[now].next[i]) {
     75                 p = tree[now].next[i];
     76                 if (now)
     77                     tree[p].fail = tree[tree[now].fail].next[i];
     78                 tree[p].end |= tree[tree[p].fail].end;
     79                 q.push(p);
     80             } else
     81                 tree[now].next[i] = tree[tree[now].fail].next[i];
     82         }
     83     }
     84 }
     85 void DoIt(int m) {
     86     int i, j, p;
     87     a.Zero();
     88     for (i = 0; i <= size; i++) {
     89         for (j = 0; j < 4; j++) {
     90             if (!tree[i].end) {
     91                 p = tree[i].next[j];
     92                 if (p) {
     93                     if (!tree[p].end)
     94                         a.mat[i][p]++;
     95                 } else
     96                     a.mat[i][0]++;
     97             }
     98         }
     99     }
    100     b.Zero();
    101     b.Unit();
    102     for (; m; m >>= 1) {
    103         if (m & 1)
    104             b = b * a;
    105         a = a * a;
    106     }
    107 }
    108 int main() {
    109     LL ans;
    110     int n, m, i;
    111     while (~scanf("%d%d", &n, &m)) {
    112         tree[0].Init();
    113         for (size = i = 0; i < n; i++) {
    114             scanf(" %s", str);
    115             Insert(str);
    116         }
    117         BFS();
    118         DoIt(m);
    119         for (ans = i = 0; i <= size; i++)
    120             ans += b.mat[0][i];
    121         printf("%lld\n", ans % MOD);
    122     }
    123     return 0;
    124 }
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  • 原文地址:https://www.cnblogs.com/DrunBee/p/2622465.html
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