zoukankan      html  css  js  c++  java
  • hdu 2095 find your present (2)

    题目连接

    http://acm.hdu.edu.cn/showproblem.php?pid=2095  

    hdu 2095 find your present (2)

    Description

    In the new year party, everybody will get a "special present".Now it's your turn to get your special present, a lot of presents now putting on the desk, and only one of them will be yours.Each present has a card number on it, and your present's card number will be the one that different from all the others, and you can assume that only one number appear odd times.For example, there are 5 present, and their card numbers are 1, 2, 3, 2, 1.so your present will be the one with the card number of 3, because 3 is the number that different from all the others.

    Input

    The input file will consist of several cases. 
    Each case will be presented by an integer n (1<=n<1000000, and n is odd) at first. Following that, n positive integers will be given in a line, all integers will smaller than 2^31. These numbers indicate the card numbers of the presents.n = 0 ends the input.

    Output

    For each case, output an integer in a line, which is the card number of your present.

    Sample Input

    5
    1 1 3 2 2
    3
    1 2 1
    0

    Sample Output

    3
    2

    哈希

    #include<algorithm>
    #include<iostream>
    #include<cstdlib>
    #include<cstring>
    #include<cstdio>
    #include<vector>
    #include<map>
    using std::map;
    using std::min;
    using std::find;
    using std::pair;
    using std::vector;
    using std::multimap;
    #define pb(e) push_back(e)
    #define sz(c) (int)(c).size()
    #define mp(a, b) make_pair(a, b)
    #define all(c) (c).begin(), (c).end()
    #define iter(c) __typeof((c).begin())
    #define cls(arr, val) memset(arr, val, sizeof(arr))
    #define cpresent(c, e) (find(all(c), (e)) != (c).end())
    #define rep(i, n) for(int i = 0; i < (int)n; i++)
    #define tr(c, i) for(iter(c) i = (c).begin(); i != (c).end(); ++i)
    const int N = 1000007;
    const int INF = 0x3f3f3f3f;
    int arr[N];
    struct Hash_Set {
        int tot, num[N], head[N], next[N];
        inline void init(int n) {
            tot = 0;
            rep(i, n + 1) head[i] = -1;
        }
        inline void insert(int val) {
            int u = val % N;
            num[tot] = u, next[tot] = head[u], head[u] = tot++;
        }
        inline bool find(int val) {
            int tot = 0, u = val % N;
            for(int i = head[u]; ~i; i = next[i]) {
                if(num[i] == val) tot++;
                if(tot >= 2) return true;
            }
            return false;
        }
    }hash;
    int main() {
    #ifdef LOCAL
        freopen("in.txt", "r", stdin);
        freopen("out.txt", "w+", stdout);
    #endif
        int n;
        while(~scanf("%d", &n), n) {
            hash.init(n);
            rep(i, n) {
                scanf("%d", &arr[i]);
                hash.insert(arr[i]);
            }
            rep(i, n) {
                if(!hash.find(arr[i])) {
                    printf("%d
    ", arr[i]);
                    break;
                }
            }
        }
        return 0;
    }
    

    stl

    #include<algorithm>
    #include<iostream>
    #include<cstdlib>
    #include<cstring>
    #include<cstdio>
    #include<vector>
    #include<map>
    using std::map;
    using std::min;
    using std::find;
    using std::pair;
    using std::vector;
    using std::multimap;
    #define pb(e) push_back(e)
    #define sz(c) (int)(c).size()
    #define mp(a, b) make_pair(a, b)
    #define all(c) (c).begin(), (c).end()
    #define iter(c) __typeof((c).begin())
    #define cls(arr, val) memset(arr, val, sizeof(arr))
    #define cpresent(c, e) (find(all(c), (e)) != (c).end())
    #define rep(i, n) for(int i = 0; i < (int)n; i++)
    #define tr(c, i) for(iter(c) i = (c).begin(); i != (c).end(); ++i)
    const int N = 1000007;
    const int INF = 0x3f3f3f3f;
    map<int, int> A;
    map<int, int>::iterator it;
    int main() {
    #ifdef LOCAL
        freopen("in.txt", "r", stdin);
        freopen("out.txt", "w+", stdout);
    #endif
        int n, v;
        while(~scanf("%d", &n), n) {
            rep(i, n) {
                scanf("%d", &v);
                A[v]++;
            }
            for(it = A.begin(); it != A.end(); ++it) {
                if(it->second == 1) {
                    printf("%d
    ", it->first);
                    break;
                }
            }
            A.clear();
        }
        return 0;
    }
  • 相关阅读:
    InterLockedIncrement and InterLockedDecrement函数原理
    矩阵文件书写的简洁代码
    注册自定义URL协议(zhuan)
    求整数的位数
    WinExec unicode 处理
    C++中如何获取对象的名字(变量名,注意不是类名)
    计算所与北大往事回顾
    不尚贤在人事管理中的作用
    寻找适合自己的无资金创业之路
    诺基亚:用薪酬激励员工
  • 原文地址:https://www.cnblogs.com/GadyPu/p/4792779.html
Copyright © 2011-2022 走看看