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  • 连分数(分数类模板) uva6875

      1 //连分数(分数类模板) uva6875
      2 // 题意:告诉你连分数的定义。求连分数,并逆向表示出来
      3 // 思路:直接上分数类模板。要注意ai可以小于0
      4 
      5 #include <iostream>
      6 #include <algorithm>
      7 #include <cstring>
      8 #include <cstdio>
      9 #include <vector>
     10 #include <cmath>
     11 #include <map>
     12 #include <queue>
     13 using namespace std;
     14 #define LL long long
     15 typedef pair<int,int> pii;
     16 const int inf = 0x3f3f3f3f;
     17 const int MOD = 998244353;
     18 const int N = 1020;
     19 const int maxx = 200010; 
     20 #define clc(a,b) memset(a,b,sizeof(a))
     21 const double eps = 0.025;
     22 void fre() {freopen("in.txt","r",stdin);}
     23 void freout() {freopen("out.txt","w",stdout);}
     24 inline int read() {int x=0,f=1;char ch=getchar();while(ch>'9'||ch<'0') {if(ch=='-') f=-1; ch=getchar();}while(ch>='0'&&ch<='9') {x=x*10+ch-'0';ch=getchar();}return x*f;}
     25 
     26 struct fr{
     27     LL a,b;
     28     fr(LL a_,LL b_){
     29         LL g=__gcd(a_,b_);
     30         a=a_/g;
     31         b=b_/g;
     32     }
     33     fr operator + (const fr &x){
     34         return fr(a*x.b+b*x.a,b*x.b);
     35     }
     36     fr operator -(const fr &x){
     37         return fr(a*x.b-x.a*b,b*x.b);
     38     }
     39     fr operator *(const fr &x){
     40         return fr(a*x.a,b*x.b);
     41     }
     42     fr operator /(const fr &x){
     43         return fr(a*x.b,b*x.a);
     44     }
     45     void add(LL x){
     46         a+=b*x;
     47     }
     48     LL split(){
     49         LL r=a/b;
     50         a%=b;
     51         if(a<0){
     52             r--;
     53             a+=b;
     54         }
     55         return r;
     56     }
     57     void inv(){
     58         std::swap(a,b);
     59         if(b<0){
     60             a=-a;
     61             b=-b;
     62         }
     63     }
     64     operator bool(){
     65         return a;
     66     }
     67 };
     68 LL in[11];
     69 int n,m;
     70 int main(){
     71     int cas=1;
     72     while(~scanf("%d%d",&n,&m),n&&m){
     73         for(int i=1;i<=n;i++) scanf("%lld",&in[i]);
     74         fr x(0,1);
     75         for(int i=n;i>=1;i--) {
     76            x.add(in[i]);
     77            if(i!=1)x.inv();
     78         }
     79 
     80         for(int i=1;i<=m;i++) scanf("%lld",&in[i]);
     81         fr y(0,1);
     82         for(int i=m;i>=1;i--) {
     83             y.add(in[i]);
     84             if(i!=1) y.inv();
     85         }
     86 
     87         fr ad=x+y,sub=x-y,mul=x*y,div=x/y;
     88         printf("Case %d:
    ",cas++);
     89         
     90         ad.inv();
     91         while(ad){
     92             ad.inv();
     93             printf("%lld",ad.split());
     94             if(ad){
     95                 printf(" ");
     96             }
     97         }
     98         printf("
    ");
     99 
    100         sub.inv();
    101         while(sub){
    102             sub.inv();
    103             printf("%lld",sub.split());
    104             if(sub){
    105                 printf(" ");
    106             }
    107         }
    108         printf("
    ");
    109 
    110         mul.inv();
    111         while(mul){
    112             mul.inv();
    113             printf("%lld",mul.split());
    114             if(mul){
    115                 printf(" ");
    116             }
    117         }
    118         printf("
    ");
    119 
    120         div.inv();
    121         while(div){
    122             div.inv();
    123             printf("%lld",div.split());
    124             if(div){
    125                 printf(" ");
    126             }
    127         }
    128         printf("
    ");
    129     
    130     }
    131     return 0;
    132 }
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  • 原文地址:https://www.cnblogs.com/ITUPC/p/5874916.html
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