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  • CODEVS 1080 (单点更新+区间查询)

    题目链接:http://codevs.cn/problem/1080/

    #include <cstdio>
    #include <iostream>
    #include <algorithm>
    #include <cmath>
    #include <queue>
    #include <vector>
    #include <cstring>
    #include <map>
    #define mem(a) memset(a,0,sizeof(a))
    using namespace std;
    typedef long long lll;
    const int maxn = 4000005;
    const lll INF = 0x3f3f3f3f3f;
    int dir[8][2]= {0,1,1,0,0,-1,-1,0,1,-1,-1,-1,1,1,-1,1};
    int dir2[4][2]= {0,1,0,-1,1,0,-1,0};
    bool flag;
    int a[maxn],sum[maxn],n,ans,num[maxn],b[maxn];
    void pushup(int k)
    {
        sum[k] = sum[k*2] + sum[k*2+1];
    }
    void build(int k,int l,int r)//递归建树
    {
        if(l == r)
        {
            sum[k] = a[l];
            return ;
        }
        else
        {
            int mid = (l+r) / 2;
            build(k<<1,l,mid);
            build(k*2+1,mid+1,r);
            pushup(k);
        }
    }
    void update(int l,int r,int L,int R,int k,int v)//单点更新
    {
        if(L == l && R == r)
        {
            sum[k] += v;
            return ;
        }
        else
        {
            int mid = (L + R) / 2;
            if(l <= mid) update(l,r,L,mid,k*2,v);
            if(mid < r) update(l,r,mid+1,R,k*2+1,v);
            pushup(k);
        }
    }
    void Search(int l,int r,int L,int R,int k)//区间查询
    {
        if(L >= l&& R <= r)
        {
            ans += sum[k];
            return;
        }
        int mid = (L + R) / 2;
        if(mid >= l)  Search(l,r,L,mid,k*2);
        if(mid < r)  Search(l,r,mid+1,R,k*2+1);
    }
    int main()
    {
        int m;
        cin >> n;
        for(int i = 1; i <= n; i++)
        {
            cin >> a[i];
        }
        mem(sum);
        build(1,1,n);//建树
        int z,x,c;
        cin >> m;
        for(int i = 1; i <= m; i++)
        {
            cin >> z >> x >> c;
            if(z == 1)
                update(x,x,1,n,1,c);
            else
            {
                ans = 0;
               Search(x,c,1,n,1);
               cout << ans << endl;
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/LLLAIH/p/11321763.html
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