Given three integers A, B and C in [−263,263], you are supposed to tell whether A+B>C.
Input Specification:
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line Case #X: true
if A+B>C, or Case #X: false
otherwise, where X is the case number (starting from 1).
Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false
思路
- 看
a,b,c
的范围就知道就算使用long long
也是要溢出的,这里我尝试取巧地使用了long double
,double
在我的codeblock上是8字节,而long double
是12字节,不知道OJ上的是怎么样的,试着用一下还过了…
代码
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
long double a,b,c;
cin >> n;
for(int i=1;i<=n;i++)
{
cin >> a >> b >> c;
if(a + b > c)
cout << "Case #" << i <<": true" << endl;
else
cout << "Case #" << i <<": false" << endl;
}
return 0;
}
引用
https://pintia.cn/problem-sets/994805342720868352/problems/994805406352654336