网站接入qq登录可以省去注册账号，增加网站的体验度。那么要实现我自己搭建的站点天天博客的qq单点登录需要以下几个步骤：
1，申请appid和appkey
首先要去https://connect.qq.com/去申请一个网站的qq接入，申请成功时会给一个appid和appkey，前提是要有一个站点。
2，qq登录跳转
申请成功后，开始进行qq登录开发，根据官方文档，需要在放置一个qq登录的图标，然后点击这个图标跳转qq认证登录页。
如下图：
点击登录之后会跳转到相应的页面如下：要确保你的回调页面和申请里面写的一样并且要将url进行URLEncode
当qq登录成功后悔跳转到回调页面，并且会在url里面带上上Authorization Code的值。
3，获取AccessToken
通过Authorization Code获取Access Token，我选择通过后端代码调用，因为前段会出现跨域问题，以下是我的封装的方法
/// <summary>
/// 获取AccessToken
/// </summary>
/// <param name="authorizationCode"></param>
/// <returns></returns>
public static async Task<string> GetAccessToken(string authorizationCode)
{
if (string.IsNullOrEmpty(authorizationCode))
throw new AuthException("qq认证登录失败：authorizationCode为空");
string url = string.Format("https://graph.qq.com/oauth2.0/token?" +
"grant_type=authorization_code&client_id={0}&client_secret={1}&code={2}&redirect_uri={3}&fmt=json", appId, appKey, authorizationCode, redirectUrl);
HttpClient httpClient = new HttpClient();
string response = await httpClient.GetStringAsync(url);
dynamic result = JsonHelper.DeserializeObject(response);
string error = result.error;
if (!string.IsNullOrEmpty(error))
throw new AuthException("qq认证登录失败：" + result.error_description);
return result.access_token;
}
4，获取openid
通过token获取openid，其中openid就想当与一个qq号码，唯一的：
/// <summary>
/// 获取OpenId
/// </summary>
/// <param name="authorizationCode"></param>
/// <returns></returns>
public static async Task<string> GetOpenId(string accessToken)
{
if (string.IsNullOrEmpty(accessToken))
throw new AuthException("qq认证登录失败：accessToken无效");
string url = "https://graph.qq.com/oauth2.0/me?fmt=json&access_token=" + accessToken;
HttpClient httpClient = new HttpClient();
string response = await httpClient.GetStringAsync(url);
dynamic result = JsonHelper.DeserializeObject(response);
string error = result.error;
if (!string.IsNullOrEmpty(error))
throw new AuthException("qq认证登录失败："+result.error_description);
return result.openid;
}
5，通过token和openid获取qq信息：
/// <summary>
/// 获取qq信息
/// </summary>
/// <param name="authorizationCode"></param>
/// <returns></returns>
public static async Task<UserModel> GetQQUser(string accessToken,string openId)
{
if (string.IsNullOrEmpty(accessToken))
throw new AuthException("accessToken无效");
if (string.IsNullOrEmpty(openId))
throw new AuthException("openId");
string url = string.Format("https://graph.qq.com/user/get_user_info" +
"?access_token={0}&openid={1}&appid={2}&fmt=json", accessToken, openId, appId);
HttpClient httpClient = new HttpClient();
string response = await httpClient.GetStringAsync(url);
dynamic result = JsonHelper.DeserializeObject(response);
if (result.ret != 0)
throw new AuthException("qq认证登录失败：" + result.msg);
UserModel userModel = new UserModel();
userModel.Account = openId;
userModel.Username = result.nickname;
userModel.LoginType = Blog.Domain.Core.LoginType.QQ;
userModel.Sex = result.gender;
userModel.HeadPhoto = result.figureurl_qq_2;
return userModel;
}
6，处理qq信息
到此，qq账号的信息以及获取完成了，接下来就是根据自己的业务来处理qq账号信息了，我选择将qq信息存入user表，后端将qq信息转为对应的user，放入jwt里面生成token:
[Route("login/{code}")]
[HttpGet]
public async Task<ApiResult> Login(string code)
{
string accessToken =await QQClient.GetAccessToken(code);
string openId = await QQClient.GetOpenId(accessToken);
UserModel userModel = await QQClient.GetQQUser(accessToken, openId);
_userService.Insert(userModel);
IList<Claim> claims = new List<Claim>()
{
new Claim("account", userModel.Account),
new Claim("username", userModel.Username),
new Claim("sex", userModel.Sex),
new Claim("birthDate",string.IsNullOrEmpty(userModel.BirthDate)?"":userModel.BirthDate),
new Claim("email", string.IsNullOrEmpty(userModel.Email)?"":userModel.Email),
new Claim("sign", string.IsNullOrEmpty(userModel.Sign)?"":userModel.Sign),
new Claim("phone",string.IsNullOrEmpty(userModel.Phone)?"":userModel.Phone),
new Claim("headPhoto", string.IsNullOrEmpty(userModel.HeadPhoto)?"":userModel.HeadPhoto)
};
string jwtToken = new JWT(_cacheClient).CreateToken(claims);
return ApiResult.Success(jwtToken);
}
7，前端存储token
qq登录后根据你申请里面写的回调页面，qq会自动跳转到这个页面，我的回调页面就一个空白页面，加上一个loading提示，加载这个页面时，调用后端api，进行认证操作，成功后，存入token并且跳转到网站首页：
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width = device-width" />
<title>qq认证登录中...</title>
<link rel="icon" href="/style/images/title.png">
</head>
<body>
<div>
qq认证登录中...
</div>
<script src="/style/js/jquery.js"></script>
<script src="/style/layui/layui.js"></script>
<script src="/style//js/request.js?v=20112171144"></script>
<script src="/style/js/util.js?v=202009091015"></script>
<script>
layui.use(["layer"], function () {
var layer = layui.layer;
var loading = layer.load(2,{offset: ['100px', '720px']});
var code = getSearchString('code');
if(code==undefined){
layer.msg('code无效', { icon: 5 });
return;
}
$.ajax({
url: url + 'qq/login/' + code,
type: 'get',
dataType: 'json',
success: function (res) {
if (res.code == "200") {
localStorage.setItem("token", res.data);
window.location.href = "../home/index.html";
}
else {
layer.close(loading)
layer.msg(res.message, { icon: 5 });
}
}
})
})
</script>
</body>
</html>
通过以上操作，我的个人站点：http://www.ttblog.site已经是完成了qq接入的功能，这只是我自己摸索出来的实现方式，给以参考，设计之中难免有不合理之处，希望有人能给出建议。