A. Petr and a calendar
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.
Input
The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).
Output
Print single integer: the number of columns the table should have.
Examples
input
1 7
output
6
input
1 1
output
5
input
11 6
output
5
Note
The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough.
1 //2017.01.31 2 #include <iostream> 3 #include <cstdio> 4 #include <cstring> 5 6 using namespace std; 7 8 int mouth[15] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; 9 10 int main() 11 { 12 int m, d; 13 while(cin>>m>>d) 14 { 15 int ans = (mouth[m]-(7-d+1)-1)/7+1+1; 16 cout<<ans<<endl; 17 } 18 19 return 0; 20 }