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  • [Leetcode] Swap Nodes in Pairs

    Given a linked list, swap every two adjacent nodes and return its head.

    For example,
    Given 1->2->3->4, you should return the list as 2->1->4->3.

    Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

     1 /**
     2  * Definition for singly-linked list.
     3  * public class ListNode {
     4  *     int val;
     5  *     ListNode next;
     6  *     ListNode(int x) {
     7  *         val = x;
     8  *         next = null;
     9  *     }
    10  * }
    11  */
    12 public class Solution {
    13     public ListNode swapPairs(ListNode head) {
    14          ListNode dummy=new ListNode(0);
    15         dummy.next=head;
    16         ListNode cur=dummy;
    17         while(cur.next!=null&&cur.next.next!=null){
    18             ListNode nextNode=cur.next.next;
    19             cur.next.next=nextNode.next;
    20             nextNode.next=cur.next;
    21             cur.next=nextNode;
    22             cur=cur.next.next;
    23         }
    24         return dummy.next;
    25     }
    26 }
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  • 原文地址:https://www.cnblogs.com/Phoebe815/p/4039320.html
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