Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.
For example, given n = 3, a solution set is:
"((()))", "(()())", "(())()", "()(())", "()()()"
思考:记录左右括号的数目。
class Solution {
public:
void func(vector<string> &res,string ans,int left,int right)
{
if(left==0&&right==0)
{
res.push_back(ans);
return;
}
if(left>0) func(res,ans+'(',left-1,right+1);
if(right>0) func(res,ans+')',left,right-1);
}
vector<string> generateParenthesis(int n) {
vector<string> res;
string ans="";
func(res,ans,n,0);
return res;
}
};