Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.
For example, given n = 3, a solution set is:
"((()))", "(()())", "(())()", "()(())", "()()()"
思考:记录左右括号的数目。
class Solution { public: void func(vector<string> &res,string ans,int left,int right) { if(left==0&&right==0) { res.push_back(ans); return; } if(left>0) func(res,ans+'(',left-1,right+1); if(right>0) func(res,ans+')',left,right-1); } vector<string> generateParenthesis(int n) { vector<string> res; string ans=""; func(res,ans,n,0); return res; } };