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  • CF1286A Garland

     Garland

     1 #include <cstdio>
     2 #include <iostream>
     3 #include <cstdio>
     4 #include <algorithm>
     5 #include <functional>
     6 #include <set>
     7 #include <vector>
     8 #include <queue>
     9 #include <cstring>
    10 #include <stack>
    11 #include <climits>
    12  
    13 using namespace std;
    14  
    15 #define ll long long
    16 #define pb push_back
    17 #define fi first
    18 #define se second
    19 
    20 //dp[i][j][0/1] 表示前i位数字中有j位偶数,且当前是偶/奇数
    21 
    22 void solve(){
    23 
    24     // int T;
    25     // cin >> T;
    26     // while(T--){
    27         int n;
    28         cin >> n;
    29         vector<int > a(n);
    30         for(auto& x : a) cin >> x;
    31         vector<vector<vector<int > > > dp(n + 1, vector<vector<int> >(n + 1, vector<int >(2, 1e9)));
    32         dp[0][0][0] = dp[0][0][1] = 0;
    33         for(int i = 1; i <= n; ++i){
    34             for(int j = 0; j <= i; ++j){
    35                 if(a[i - 1] % 2 == 1 || a[i - 1] == 0){
    36                     dp[i][j][1] = min(dp[i - 1][j][0] + 1, dp[i - 1][j][1]);
    37                 }
    38                 if(a[i - 1] % 2 == 0 && j > 0){
    39                     dp[i][j][0] = min(dp[i - 1][j - 1][1] + 1, dp[i - 1][j - 1][0]);
    40                 }
    41             }
    42         }
    43         cout << max(dp[n][n ][1], dp[n][n][0]) << endl;
    44         // cout << dp[n][n][1] << endl;
    45         // cout << dp[n][n][0] << endl;
    46 
    47     // }
    48 }
    49  
    50 int main(){
    51     
    52     // freopen("C:\Users\admin\Desktop\input.txt", "r", stdin);
    53     // freopen("C:\Users\admin\Desktop\output.txt", "w", stdout);
    54     ios::sync_with_stdio(false);
    55     cin.tie(0);
    56     cout.tie(0);
    57     solve();
    58     
    59     return 0;
    60 }
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  • 原文地址:https://www.cnblogs.com/SSummerZzz/p/12859109.html
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