ACM:Protecting the Flowers

Farmer John went to cut some wood and left N (2 ≤ N ≤ 100,000) cows eating the grass, as usual. When he returned, he found to his horror that the cluster of cows was in his garden eating his beautiful flowers. Wanting to minimize the subsequent damage, FJ decided to take immediate action and transport each cow back to its own barn.

Each cow i is at a location that is T_i minutes (1 ≤ T_i ≤ 2,000,000) away from its own barn. Furthermore, while waiting for transport, she destroys D_i (1 ≤D_i ≤ 100) flowers per minute. No matter how hard he tries, FJ can only transport one cow at a time back to her barn. Moving cow i to its barn requires 2 × T_i minutes (T_i to get there and T_i to return). FJ starts at the flower patch, transports the cow to its barn, and then walks back to the flowers, taking no extra time to get to the next cow that needs transport.

Write a program to determine the order in which FJ should pick up the cows so that the total number of flowers destroyed is minimized.

Input

Line 1: A single integer N  Lines 2..N+1: Each line contains two space-separated integers, T_i and D_i, that describe a single cow's characteristics

Output

Line 1: A single integer that is the minimum number of destroyed flowers

#include <iostream>
#include <algorithm>
using namespace std;
 structabc
 {
    int t,d;
    double b;
 }f[100000+10];
 bool cmp (abc const x,abc const y)
 {
     if (x.b<y.b)
        return true ;
    else return false ;
 }
int main()
{
    int n;
    while(cin>>n)
       {
           int *t = new int[n];
           int *d = new int[n];
           double *b = new double[n];
           int total = 0;
           for(int i = 0 ; i< n;i++)
           {
               cin>>f[i].t>>f[i].d;
               total += f[i].d;
               f[i].b = (f[i].t*1.000)/f[i].d;
           }
          sort (f,f+n,cmp);
          long long count = 0;
          for(int i = 0 ; i < n ; i++)
          {
              count += 2 * f[i].t * (total - f[i].d);
              total = total - f[i].d;
          }
        cout<<count<<endl;
       }
   return 0;
}

学会使用#include<algroithm>中的Sort在（快排）排序。以及问题解决的思路，怎么得到最好的方案，这里是根据t[i]/d[i]来得到的。