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  • 和集 (Sumsets,UVa 10125)

     1 #include <iostream>
     2 #include <string.h>
     3 #include <string>
     4 #include <fstream>
     5 #include <algorithm>
     6 #include <stdio.h>
     7 #include <vector>
     8 #include <queue>
     9 #include <set>
    10 #include <cmath>
    11 using namespace std;
    12 const double eps = 1e-8;
    13 const int INF=0x7fffffff;
    14 #define MAXN 1002
    15 int s[MAXN];
    16 int main()
    17 {
    18     int n;
    19     while(scanf("%d",&n),n!=0)
    20     {
    21         for(int i=0;i<n;i++)
    22         scanf("%d",&s[i]);
    23         sort(s,s+n);
    24         bool found=false;
    25         int ans=0,a,b,c,d;
    26         for(d=n-1;d>=0;d--)
    27         {
    28             for(a=n-1;a>1;a--)
    29             if(d!=a){
    30                 ans=s[d]-s[a];
    31             for(b=0,c=a-1;b<c;)
    32             {
    33                 if(s[b]+s[c]==ans){found=true;break;}
    34                 else if(s[b]+s[c]<ans)b++;
    35                 else c--;
    36             }
    37             if(found)break;
    38             }
    39             if(found)break;
    40         }
    41         if(found)printf("%d
    ",s[d]);
    42         else printf("no solution
    ");
    43 
    44     }
    45     return 0;
    46 }

    拆分 d-a=b+c

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  • 原文地址:https://www.cnblogs.com/TO-Asia/p/3197829.html
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