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  • HDU 1000 & HDU1001 & 字符串连接

    A + B Problem

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 571020    Accepted Submission(s): 181151


    Problem Description
    Calculate A + B.
     
    Input
    Each line will contain two integers A and B. Process to end of file.
     
    Output
    For each case, output A + B in one line.
     
    Sample Input
    1 1
     
    Sample Output
    2
    #include <iostream>
    #include <cstdio>
    
    using namespace std;
    
    int main()
    {
        int a=1,b=1;
        while(scanf("%d %d",&a,&b)!=EOF){
            printf("%d
    ",a+b);
        }
        return 0;
    }
    View Code

    Sum Problem

    Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 410639    Accepted Submission(s): 103262


    Problem Description
    Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

    In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
     
    Input
    The input will consist of a series of integers n, one integer per line.
     
    Output
    For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
     
    Sample Input
    1 100
     
    Sample Output
    1 5050
    #include <iostream>
    #include <cstdio>
    using namespace std;
    
    int main()
    {
        int t;
        int sum=0;
        while(scanf("%d",&t)!=EOF){
            for(int i=1;i<=t;i++){
                sum+=i;
            }
            printf("%d
    
    ",sum);
            sum=0;
        }
        return 0;
    }
    View Code

    字符串连接:

    #include <iostream>
    #include <cstdio>
    
    using namespace std;
    
    int main()
    {
        char a[20]="i love";
        char b[20]="you!";
        char c[40];
        sprintf(c,"%s %s",a,b);
        printf("%s",c);
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/TWS-YIFEI/p/5590030.html
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