Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
1为了操作方便,我们给拼接后的新链表添加一个头结点 本文地址
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) {
//为操作方便,添加一个头节点
ListNode node(0), *p = &node;
while(l1 && l2)
{
if(l1->val < l2->val)
{
p->next = l1;
l1 = l1->next;
}
else
{
p->next = l2;
l2 = l2->next;
}
p = p->next;
}
if(l1)p->next = l1;
else if(l2)p->next = l2;
return node.next;
}
};
【版权声明】转载请注明出处: http://www.cnblogs.com/TenosDoIt/p/3673050.html