Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
1为了操作方便,我们给拼接后的新链表添加一个头结点 本文地址
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { //为操作方便,添加一个头节点 ListNode node(0), *p = &node; while(l1 && l2) { if(l1->val < l2->val) { p->next = l1; l1 = l1->next; } else { p->next = l2; l2 = l2->next; } p = p->next; } if(l1)p->next = l1; else if(l2)p->next = l2; return node.next; } };
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