C. Help Farmer
简化题意：已知abc=N，给出N，求解出
[(a+2)*(b+2)*(c+1) 的最大值和最小值
]
题解：暴力枚举a，b，c，求出最小值。
默认
[最大值 =3*3*(N+1)
]
#include <cstdio>
#include <queue>
using namespace std;
typedef long long ll;
ll min(ll a,ll b){
return a<b?a:b;
}
ll max(ll a,ll b){
return a>b?a:b;
}
int main(){
ll N;
scanf("%lld",&N);
ll minn=3*3*(N+1);
for(ll a=1;a<=100000;a++){
if(N%a==0)
for(ll b=1;b<=10000;b++){
if(N%(a*b)==0){
ll c=N/a/b;
minn=min(minn,(min(min(a,b),c)+1)*(max(max(a,b),c)+2)*
(a+b+c-min(min(a,b),c)-max(max(a,b),c)+2));
}
}
}
printf("%lld",minn-N);
printf(" %lld
",3*3*(N+1)-N);
return 0;
}