zoukankan      html  css  js  c++  java
  • Train Problem I

    Train Problem I

    Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other)
    Total Submission(s) : 35   Accepted Submission(s) : 14

    Font: Times New Roman | Verdana | Georgia

    Font Size:  

    Problem Description

    As the new term comes, the Ignatius Train Station is very busy nowadays. A lot of student want to get back to school by train(because the trains in the Ignatius Train Station is the fastest all over the world ^v^). But here comes a problem, there is only one railway where all the trains stop. So all the trains come in from one side and get out from the other side. For this problem, if train A gets into the railway first, and then train B gets into the railway before train A leaves, train A can't leave until train B leaves. The pictures below figure out the problem. Now the problem for you is, there are at most 9 trains in the station, all the trains has an ID(numbered from 1 to n), the trains get into the railway in an order O1, your task is to determine whether the trains can get out in an order O2.

    Input

    The input contains several test cases. Each test case consists of an integer, the number of trains, and two strings, the order of the trains come in:O1, and the order of the trains leave:O2. The input is terminated by the end of file. More details in the Sample Input.

    Output

    The output contains a string "No." if you can't exchange O2 to O1, or you should output a line contains "Yes.", and then output your way in exchanging the order(you should output "in" for a train getting into the railway, and "out" for a train getting out of the railway). Print a line contains "FINISH" after each test case. More details in the Sample Output.

    Sample Input

    3 123 321
    3 123 312
    

    Sample Output

    Yes.
    in
    in
    in
    out
    out
    out
    FINISH
    No.
    FINISH
    

    Hint

    Hint For the first Sample Input, we let train 1 get in, then train 2 and train 3. So now train 3 is at the top of the railway, so train 3 can leave first, then train 2 and train 1. In the second Sample input, we should let train 3 leave first, so we have to let train 1 get in, then train 2 and train 3. Now we can let train 3 leave. But after that we can't let train 1 leave before train 2, because train 2 is at the top of the railway at the moment. So we output "No.".

    Author

    Ignatius.L
     1 #include <stdio.h>
     2 #include <stdlib.h>
     3 #include <string.h>
     4 
     5 int main()
     6 {
     7     int NUM,Len,i,j,k,sign,Top;
     8     char str[10000],flat[10000],FLAT[10000],SIGN[10000];
     9     while(scanf("%d",&NUM)!=EOF)
    10     {
    11         memset(flat,0,sizeof(flat));
    12         memset(FLAT,0,sizeof(FLAT));
    13         memset(FLAT,0,sizeof(FLAT));
    14         getchar();
    15         scanf("%s%s",flat,FLAT);
    16             for(i=0,j=0,k=0,sign=0,Top=0;k<=NUM&&j<=NUM;)
    17             {
    18                 if(Top>=0&&k>0&&str[Top]==FLAT[j])
    19                 {
    20                     str[Top]='';
    21                     Top-=1;k-=1;j++;
    22                     if(Top==0&&j>=NUM)break;
    23                     SIGN[sign++]=1;
    24                 }
    25                 else
    26                     {str[k++]=flat[i++];Top=k-1;SIGN[sign++]=0;}
    27                 str[k]='';
    28             }
    29              str[k]='';
    30              if(str[0]=='')
    31             {
    32                 printf("Yes.
    ");
    33                 for(i=0;i<sign-2;i++)
    34                 if(SIGN[i]==0)
    35                     printf("in
    ");
    36                 else if(SIGN[i]==1)
    37                     printf("out
    ");
    38 
    39             }
    40              else
    41                 printf("No.
    ");
    42         printf("FINISH
    ");
    43     }
    44 
    45 
    46 
    47 }
    View Code
    转载请备注:
    **************************************
    * 作者: Wurq
    * 博客: https://www.cnblogs.com/Wurq/
    * Gitee: https://gitee.com/wurq
    **************************************
  • 相关阅读:
    gcc 编译
    UltraEdit 添加到右键菜单
    linux 编译错误:undefined reference to `__gxx_personality_v0'
    UltraEdit 取消生成.bak文件
    容器
    Windows CEvent事件
    Windows _beginthreadex 线程类与线程池
    C++ 工厂模式
    Mutex linux线程锁
    windows CRITICAL_SECTION 线程锁
  • 原文地址:https://www.cnblogs.com/Wurq/p/3750317.html
Copyright © 2011-2022 走看看