uva11827gcd

gcd裸题，不过输入要注意gets会tle，要用快速读入

#include<map>
#include<set>
#include<cmath>
#include<queue>
#include<stack>
#include<vector>
#include<cstdio>
#include<cassert>
#include<iomanip>
#include<cstdlib>
#include<cstring>
#include<iostream>
#include<algorithm>
#define pi acos(-1.0)
#define ll long long
#define mod 1000000007
#define ls l,m,rt<<1
#define rs m+1,r,rt<<1|1
#pragma comment(linker, "/STACK:1024000000,1024000000")

using namespace std;

const double g=10.0,eps=1e-7;
const int N=100000+10,maxn=500+100,inf=0x3f3f3f;

ll a[N];
ll gcd(ll a,ll b)
{
    if(a<b)swap(a,b);
    return b?gcd(b,a%b):a;
}
int main()
{
  /*  ios::sync_with_stdio(false);
    cin.tie(0);*/
    ll n,ans=0;
    scanf("%d",&n);
    while (getchar() != '\n');
    while (n --) {
        char buf;
        int cnt = 0;
        while ((buf = getchar()) != '\n')
        if (buf >= '0' && buf <= '9') {
        ungetc(buf,stdin);
        scanf("%d",&a[cnt++]);
        }
        ll ans=0;
        for(int i=0;i<cnt;i++)
            for(int j=i+1;j<cnt;j++)
                ans=max(ans,gcd(a[i],a[j]));
        printf("%lld\n",ans);
    }
    return 0;
}
/*********************
3
10 20 30 40
7 5 12
125 15 25
*********************/