You are given a standard 12-hour clock with analog display, an hour hand and a minute hand. How many times does the minute hand pass the hour hand in a given time interval?
Sample Input
12 50 1 2 3 8 3 20 2 45 11 0 11 0 3 20 1 2 12 50 3 20 3 8
Sample Output
Program 3 by team X
Initial time Final time Passes
12:50 01:02 0
03:08 03:20 1
02:45 11:00 8
11:00 03:20 4
01:02 12:50 11
03:20 03:08 10
End of program 3 by team X
题目的下边还有一大段，当时出在HUST上，根本分不清哪输出格式是哪个，谁知道最前边最后边那句话也需要。当时有一次试了一下加上这两句，其他地方哪里又出错了。看了题解，直接把最后一次提交的错误代码， 加上这两句输出，直接A了，坑
判断分针和时针相遇的次数
代码如下：
1 # include <iostream> 2 # include<cstdio> 3 # include<cstring> 4 using namespace std; 5 6 int main() 7 { 8 int a,b,c,d,ans; 9 double tmp1,tmp2,tmp3,tmp4; 10 printf("Program 3 by team X "); 11 printf("Initial time Final time Passes "); 12 while(scanf("%d%d%d%d",&a,&b,&c,&d)!= EOF) 13 { 14 printf(" "); 15 printf("%02d:%02d",a,b); 16 printf(" "); 17 printf("%02d:%02d",c,d); 18 printf(" "); 19 if(a==12) 20 a=0; 21 if(c==12) 22 c=0; 23 tmp2 = b/60.0; 24 tmp1 = a/12.0 + tmp2/12.0; 25 tmp4 = d/60.0; 26 tmp3 = c/12.0 + tmp4/12.0; 27 if(a==c) 28 { 29 if(d>=b) 30 { 31 if(tmp1-tmp2>0 && tmp4-tmp3>0) 32 { 33 ans = 1; 34 } 35 else 36 ans = 0; 37 } 38 else 39 { 40 ans = 10; 41 if(tmp1 - tmp2 > 0 ) 42 ans++; 43 if(tmp4-tmp3>0) 44 ans ++; 45 } 46 } 47 else if(a<c) 48 { 49 ans = c-a-1; 50 if(tmp1 - tmp2 > 0 ) 51 ans++; 52 if(tmp4 - tmp3 > 0) 53 ans++; 54 } 55 else 56 { 57 ans = 11-a + c -1; 58 if(tmp1 - tmp2 >0 ) 59 ans++; 60 if(tmp4 - tmp3>0) 61 ans++; 62 } 63 printf("%2d ",ans); 64 } 65 printf("End of program 3 by team X "); 66 return 0; 67 }