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  • MySQL复杂用法

      今天学了几个MySQL的复杂用法,具体叫什么名字已经记不太清了=-= 但是语法还是记住了。感觉今天学的语法并不是最重要的 ,逻辑才是。只要逻辑理清了 像是一个问题 分为几步 找到哪是第一步,哪是第二步,哪是第三步等 剩下的就是把每一步的语句拼凑起来。不过我感觉这是个有点笨办法,不过个人感觉比较清晰,毕竟还没有那么强的逻辑能力 不像一些大神直接一步搞定了。

      明天要写需求文档了,感觉略显蛋疼。身为一个标准宅男,沟通能力实在堪忧。不知道该问一些什么问题,略显蛋疼,还有有时候问的太细会不会被客户按在地上摩擦摩擦啊 囧。

      说一下目前对需求文档的理解吧:

      主要是针对客户,确定客户的具体需求。

      业务需求概述:为什么公司开发一个什么类型的能干什么的软件。

      功能说明:这个软件都能做些什么(大体)。

      业务流程:这个软件都能做什么(具体)。

        目前就只能理解到这里,也不知道有没有误入歧途=-=。

      剩下的拿习题顶了......

    1、 查询Student表中的所有记录的Sname、Ssex和Class列。

    Select sname, ssex, class from student;

    2、 查询教师所有的单位即不重复的Depart列。

    select distinct depart from teacher;

    3、 查询Student表的所有记录。

    Select * from student;

    4、 查询Score表中成绩在60到80之间的所有记录。

    Select * from score where degree between 60 and 80;

    5、 查询Score表中成绩为85,86或88的记录。

    Select * from score where degree = 85 or degree = 86 or degree = 88;

    6、 查询Student表中“95031”班或性别为“女”的同学记录。

    Select * from student where class = “95031” or ssex = “女”;

    7、 Class降序查询Student表的所有记录。

    select * from student order by class;

    8、 Cno升序、Degree降序查询Score表的所有记录。

    select * from score order by cno ,degree desc;

    9、 查询“95031”班的学生人数。

    select count(*) from student where class = "95031";

    10、 查询Score表中的最高分的学生学号和课程号。(子查询或者排序)

    select sno, cno from score where degree = (select max(degree) from score);

    11、 查询每门课的平均成绩。

    select cno, avg(degree) from score group by cno;

    12、查询Score表中至少有5名学生选修的并以3开头的课程的平均分数。

    select avg(degree) from score where cno in (select cno from score group by cno having count(cno) > 5) and cno like "3%";

    13、查询分数大于70,小于90的Sno列。

    select sno from score where degree > 70 and degree < 90;

    14、查询所有学生的Sname、Cno和Degree列。

    select a.sname, b.cno, b.degree from student a, score b where a.sno = b.sno;

    15、查询所有学生的Sno、Cname和Degree列。

    select a.sno, a.degree, b. cname from score a, course b where a.cno = b.cno;

    16、查询所有学生的Sname、Cname和Degree列。

    select a.sname, b.cname, c.degree from student a, course b, score c where a.sno = c.sno and b.cno = c.cno;

    17、 查询“95033”班学生的平均分。

    select avg(degree) from score where sno in (select sno from student where class = "95033");

    18、 假设使用如下命令建立了一个grade表:

    create table grade(low  int(3),upp  int(3),rank  char(1))

    insert into grade values(90,100,’A’)

    insert into grade values(80,89,’B’)

    insert into grade values(70,79,’C’)

    insert into grade values(60,69,’D’)

    insert into grade values(0,59,’E’)

    现查询所有同学的Sno、Cno和rank列。

     select a.sno, a.cno, b.rank from score a

        -> join grade b

        -> on a.degree >= b.low and a.degree <= b.upp;

    19、  查询选修“3-105”课程的成绩高于“109”号同学成绩的所有同学的记录。

    20、查询score中选学多门课程的同学中分数为非最高分成绩的记录。

     select * from score where degree not in (select max(degree) from score where cno in (select cno from score group by cno having(cno) > 1));

    21、 查询成绩高于学号为“109”、课程号为“3-105”的成绩的所有记录。

    select * from score where degree > (select degree from score where sno = 109 and cno = "3-105")

    22、查询和学号为108的同学同年出生的所有学生的Sno、Sname和Sbirthday列。

    select sno, sname, sbirthday from student where year(sbirthday) = (select year(sbirthday) from student where sno = 108);

    23、查询“张旭“教师任课的学生成绩。

     select * from score where cno = (select cno from course where tno = (select tno from teacher where tname = "张旭"));

    24、查询选修某课程的同学人数多于5人的教师姓名。

    select tname from teacher where tno = (select tno from course where cno = (select cno from score group by cno having count(cno) > 5));

    25、查询95033班和95031班全体学生的记录。

    select * from student where class in ("95033", "95031");

    26、  查询存在有85分以上成绩的课程Cno.

    select cno from score where degree > 85;

    27、查询出“计算机系“教师所教课程的成绩表。

    select * from score where cno in (select cno from course where tno in (select tno from teacher where depart = "计算机系"));

    28、查询“计算机系”与“电子工程系“不同职称的教师的Tname和Prof。

    select tname, prof from teacher where depart in ("计算机系","电子工程系") and prof in (select prof from teacher group by prof having count(prof) < 2);

    29、查询选修编号为“3-105“课程且成绩至少高于选修编号为“3-245”的同学

    select * from score where cno = "3-105" and degree >= (select max(degree) from score where cno = "3-245");

    30、Cno、Sno和Degree,并按Degree从高到低次序排序。

    30、查询选修编号为“3-105”且成绩高于选修编号为“3-245”课程的同学的Cno、Sno和Degree.

    select cno, sno, degree from score order by degree;

    31、 查询所有教师和同学的name、sex和birthday.

    select tname, tsex, tbirthday from teacher;

    select sname, ssex, sbirthday from student;

    32、查询所有“女”教师和“女”同学的name、sex和birthday.

    select tname, tsex, tbirthday from teacher where tsex = "女";

    select sname, ssex, sbirthday from student where ssex = "女";

    33、 查询成绩比该课程平均成绩低的同学的成绩表。

    select * from score where degree < (select avg(degree) from score where cno in (select cno from score)) and cno in (select cno from score);

    34、 查询所有任课教师的Tname和Depart.

    select tname, depart from teacher where tno in (select tno from course);

    35 、 查询所有未讲课的教师的Tname和Depart. 

    select tname, depart from teacher where tno not in (select tno from course);

    36、查询至少有2名男生的班号。

    select class from student where ssex >= 2;

    37、查询Student表中不姓“王”的同学记录。

    select * from student where sname not like ("%王%");

    38、查询Student表中每个学生的姓名和年龄。

    select sname, sbirthday from student;

    39、查询Student表中最大和最小的Sbirthday日期值。

    select min(sbirthday) from student;

    select max(sbirthday) from student;

    40、以班号和年龄从大到小的顺序查询Student表中的全部记录。

    select * from student order by class desc, sbirthday desc;

    41、查询“男”教师及其所上的课程。

    select a.*, b.cname from teacher a, course b where b.tno = a.tno and a.tno in (select tno from teacher where tsex = "男");

    42、查询最高分同学的Sno、Cno和Degree列。

    select * from score where degree in (select max(degree) from score);

    43、查询和“李军”同性别的所有同学的Sname.

    select sname from student where ssex = (select ssex from student where sname = "李军");

    44、查询和“李军”同性别并同班的同学Sname.
    select sname from student where class = (select class from student where sname = "李军") and ssex = (select ssex from student where sname = "李军");

    45、查询所有选修“计算机导论”课程的“男”同学的成绩表。

    select * from score where sno in (select sno from student where ssex = "男") and cno = (select cno from course where cname = "计算机导论");

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  • 原文地址:https://www.cnblogs.com/assassin3154/p/7780759.html
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