zoukankan      html  css  js  c++  java
  • Algorithm——Container With Most Water

    Q:

    Given n non-negative integers a1a2, ..., an , where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (iai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

    Note: You may not slant the container and n is at least 2.

    The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.

    Example:

    Input: [1,8,6,2,5,4,8,3,7]
    Output: 49

    A:

    JAVASCRIPT(这是log(n^2)的方法,还有很大的优化区间)

    /**
     * @param {number[]} height
     * @return {number}
     */
    var maxArea = function(numArr) {
        var h = '', w = '', tmp = 0, max = 0;
        for (var m = 0; m < numArr.length - 1; m++) {
            for (var n = m + 1; n < numArr.length; n++) {
                h = Math.min(numArr[m], numArr[n]);
                w = n - m;
                tmp = h * w;
    
                if (max < tmp) {
                    max = tmp;
                }          
            }
        }
    
        return max;         
    };

     JAVA(这是log(n)的方法)

    /**
     * Container With Most Water
     * 盛最多水的容器
    */
    
    public class Solution {
        public int maxArea(int[] height) {
            int maxarea = 0, l = 0, r = height.length - 1;
            while (l < r) {
                maxarea = Math.max(maxarea, Math.min(height[l], height[r]) * (r - l));
                if (height[l] < height[r])
                    l++;
                else
                    r--;
            }
            return maxarea;
        }
    }
    
    
  • 相关阅读:
    sql server 跨库操作
    FPGA使用技巧
    MATLAB学习(3)
    FPGA统计摄像头输出-基于MD9T112
    zedboard VmodCAM 图像采集 HDMI输出显示
    VmodCAM图像采集 VGA显示
    EDK中如何使用ISE中生成的IP
    如何将HDL文件实例化到XPS中
    ubuntu下安装 Source insight
    VmodCAM 初始化
  • 原文地址:https://www.cnblogs.com/bbcfive/p/11027874.html
Copyright © 2011-2022 走看看