zoukankan      html  css  js  c++  java
  • Sql Server 2000 用存储过程来遍历树

    create table producttype ( iproducttypeid int,iparenttypeid int, cproducttypename char(10) )

     insert producttype values(1,0,'百货')

    insert producttype values(2,1,'纺织')

    insert producttype values(3,1,'汽车')

     insert producttype values(4,1,'电器')

    insert producttype values(5,1,'医药')

     insert producttype values(6,1,'图书')

    insert producttype values(7,4,'家电')

    insert producttype values(8,4,'IT')

    insert producttype values(9,7,'电视机')

     insert producttype values(10,7,'电冰箱')

    insert producttype values(11,7,'洗衣机')

     insert producttype values(12,7,'空调')

     insert producttype values(13,7,'电风扇')

    insert producttype values(14,8,'电脑')

     insert producttype values(15,8,'网络')

     insert producttype values(16,8,'数码')

     insert producttype values(17,14,'台式')

    insert producttype values(18,14,'笔记本')

    insert producttype values(19,14,'配件')

    insert producttype values(20,14,'外设')

    insert producttype values(21,16,'照像机')

     insert producttype values(22,16,'摄像机')

    insert producttype values(23,16,'MP3播放器')

     insert producttype values(24,19,'CPU')

     insert producttype values(25,19,'主板')

    insert producttype values(26,19,'内存')

    insert producttype values(27,19,'显卡')

     insert producttype values(28,19,'声卡')

     insert producttype values(29,19,'网卡')

    insert producttype values(30,19,'硬盘')

    insert producttype values(31,19,'软驱')

    insert producttype values(32,19,'光驱')

     insert producttype values(33,19,'输出设备')

    insert producttype values(34,19,'键盘')

     insert producttype values(35,19,'鼠标')

    insert producttype values(36,19,'音箱')

    insert producttype values(37,19,'耳麦')

     insert producttype values(38,33,'打印机')

    insert producttype values(39,33,'扫描仪')

    insert producttype values(40,33,'投影仪')

    --求解一

    create function getclassinfo(@id int) returns @tabinfo table

    (

    cProductid int,

    cParentId int,

    cProductName char(10),iLevel int

    )

      as

       begin

          declare @cid int,@level int

          set @level=0

          insert @tabinfo select *,@level from producttype where iproducttypeid=@id declare cur1 cursor local for select cProductid,iLevel from @tabinfo open cur1 fetch next from cur1 into @cid,@level while @@fetch_status=0 begin insert @tabinfo select *,@level+1 from producttype where iparenttypeid=@cid fetch next from cur1 into @cid,@level end return end select * from getclassinfo(33) select * from producttype

    --求解二

     create function getclassinfo2(@id int) returns @tabinfo table (cProductid int,cParentId int,cProductName char(10),iLevel int) as begin declare @level as int set @level=0 insert @tabinfo select *,@level from producttype where iproducttypeid=@id while @@rowcount>0 begin set @level=@level+1 insert @tabinfo select x.iproducttypeid,x.iparenttypeid, x.cproducttypename,@level from producttype as x join @tabinfo as y on x.iparenttypeid=y.cProductid and y.ilevel=@level-1 end return end select * from getclassinfo2(33)

  • 相关阅读:
    JavaScript随机数
    javascript函数
    hdu 4122(RMQ)2011福州现场赛B题
    hdu 4119 (模拟+字符串)成都现场赛I题
    hdu 4118(树形dp) 成都现场赛H题
    hdu 4115(2-SAT) 2011 成都现场赛E题
    Codeforces Round #237 (Div. 2) 解题报告
    Codeforces Round #234 (Div. 2) 解题报告
    uva 1411(二分图最大权匹配)
    uva 11383(二分图最大权匹配)
  • 原文地址:https://www.cnblogs.com/canyudeai008/p/1905511.html
Copyright © 2011-2022 走看看