#coding=utf-8 #****************************************************************************** # 下面为阴历计算所需的数据,为节省存储空间,所以采用下面比较变态的存储方法. #****************************************************************************** #数组g_lunar_month_day存入阴历1901年到2050年每年中的月天数信息， #阴历每月只能是29或30天，一年用12（或13）个二进制位表示，对应位为1表30天，否则为29天 g_lunar_month_day = [ 0x4ae0, 0xa570, 0x5268, 0xd260, 0xd950, 0x6aa8, 0x56a0, 0x9ad0, 0x4ae8, 0x4ae0, #1910 0xa4d8, 0xa4d0, 0xd250, 0xd548, 0xb550, 0x56a0, 0x96d0, 0x95b0, 0x49b8, 0x49b0, #1920 0xa4b0, 0xb258, 0x6a50, 0x6d40, 0xada8, 0x2b60, 0x9570, 0x4978, 0x4970, 0x64b0, #1930 0xd4a0, 0xea50, 0x6d48, 0x5ad0, 0x2b60, 0x9370, 0x92e0, 0xc968, 0xc950, 0xd4a0, #1940 0xda50, 0xb550, 0x56a0, 0xaad8, 0x25d0, 0x92d0, 0xc958, 0xa950, 0xb4a8, 0x6ca0, #1950 0xb550, 0x55a8, 0x4da0, 0xa5b0, 0x52b8, 0x52b0, 0xa950, 0xe950, 0x6aa0, 0xad50, #1960 0xab50, 0x4b60, 0xa570, 0xa570, 0x5260, 0xe930, 0xd950, 0x5aa8, 0x56a0, 0x96d0, #1970 0x4ae8, 0x4ad0, 0xa4d0, 0xd268, 0xd250, 0xd528, 0xb540, 0xb6a0, 0x96d0, 0x95b0, #1980 0x49b0, 0xa4b8, 0xa4b0, 0xb258, 0x6a50, 0x6d40, 0xada0, 0xab60, 0x9370, 0x4978, #1990 0x4970, 0x64b0, 0x6a50, 0xea50, 0x6b28, 0x5ac0, 0xab60, 0x9368, 0x92e0, 0xc960, #2000 0xd4a8, 0xd4a0, 0xda50, 0x5aa8, 0x56a0, 0xaad8, 0x25d0, 0x92d0, 0xc958, 0xa950, #2010 0xb4a0, 0xb550, 0xb550, 0x55a8, 0x4ba0, 0xa5b0, 0x52b8, 0x52b0, 0xa930, 0x74a8, #2020 0x6aa0, 0xad50, 0x4da8, 0x4b60, 0x9570, 0xa4e0, 0xd260, 0xe930, 0xd530, 0x5aa0, #2030 0x6b50, 0x96d0, 0x4ae8, 0x4ad0, 0xa4d0, 0xd258, 0xd250, 0xd520, 0xdaa0, 0xb5a0, #2040 0x56d0, 0x4ad8, 0x49b0, 0xa4b8, 0xa4b0, 0xaa50, 0xb528, 0x6d20, 0xada0, 0x55b0, #2050 ] #数组gLanarMonth存放阴历1901年到2050年闰月的月份，如没有则为0，每字节存两年 g_lunar_month = [ 0x00, 0x50, 0x04, 0x00, 0x20, #1910 0x60, 0x05, 0x00, 0x20, 0x70, #1920 0x05, 0x00, 0x40, 0x02, 0x06, #1930 0x00, 0x50, 0x03, 0x07, 0x00, #1940 0x60, 0x04, 0x00, 0x20, 0x70, #1950 0x05, 0x00, 0x30, 0x80, 0x06, #1960 0x00, 0x40, 0x03, 0x07, 0x00, #1970 0x50, 0x04, 0x08, 0x00, 0x60, #1980 0x04, 0x0a, 0x00, 0x60, 0x05, #1990 0x00, 0x30, 0x80, 0x05, 0x00, #2000 0x40, 0x02, 0x07, 0x00, 0x50, #2010 0x04, 0x09, 0x00, 0x60, 0x04, #2020 0x00, 0x20, 0x60, 0x05, 0x00, #2030 0x30, 0xb0, 0x06, 0x00, 0x50, #2040 0x02, 0x07, 0x00, 0x50, 0x03 #2050 ] #================================================================================== from datetime import date, datetime from calendar import Calendar as Cal START_YEAR = 1901 def is_leap_year(tm): y = tm.year return (not (y % 4)) and (y % 100) or (not (y % 400)) def show_month(tm): (ly, lm, ld) = get_ludar_date(tm) print print u"%d年%d月%d日" % (tm.year, tm.month, tm.day), week_str(tm), print u" 农历：", y_lunar(ly), m_lunar(lm), d_lunar(ld) print print u"日 一 二 三 四 五 六" c = Cal() ds = [d for d in c.itermonthdays(tm.year, tm.month)] count = 0 for d in ds: print_str = ''
if count == 0 and 0 in ds:
print_str += ' '
count += 1 if d == 0: print print_str+" ", continue (ly, lm, ld) = get_ludar_date(datetime(tm.year, tm.month, d)) if count % 7 == 0: print d_str = str(d) if d == tm.day: d_str = u"*" + d_str print d_str + d_lunar(ld) + u" ", print def this_month(): show_month(datetime.now()) #www.iplaypython.com def week_str(tm): a = u'星期一 星期二 星期三 星期四 星期五 星期六 星期日'.split() return a[tm.weekday()] def d_lunar(ld): a = u'初一 初二 初三 初四 初五 初六 初七 初八 初九 初十 十一 十二 十三 十四 十五 十六 十七 十八 十九 廿十 廿一 廿二 廿三 廿四 廿五 廿六 廿七 廿八 廿九 三十'.split() return a[ld - 1] def m_lunar(lm): a = u'正月 二月 三月 四月 五月 六月 七月 八月 九月 十月 十一月 十二月'.split() return a[lm - 1] def y_lunar(ly): y = ly tg = u'甲 乙 丙 丁 戊 己 庚 辛 壬 癸'.split() dz = u'子 丑 寅 卯 辰 巳 午 未 申 酉 戌 亥'.split() sx = u'鼠 牛 虎 免 龙 蛇 马 羊 猴 鸡 狗 猪'.split() return tg[(y - 4) % 10] + dz[(y - 4) % 12] + u' ' + sx[(y - 4) % 12] + u'年' def date_diff(tm): return (tm - datetime(1901, 1, 1)).days def get_leap_month(lunar_year): flag = g_lunar_month[(lunar_year - START_YEAR) / 2] if (lunar_year - START_YEAR) % 2: return flag & 0x0f else: return flag >> 4 def lunar_month_days(lunar_year, lunar_month): if (lunar_year < START_YEAR): return 30 high, low = 0, 29 iBit = 16 - lunar_month; if (lunar_month > get_leap_month(lunar_year) and get_leap_month(lunar_year)): iBit -= 1 if (g_lunar_month_day[lunar_year - START_YEAR] & (1 << iBit)): low += 1 if (lunar_month == get_leap_month(lunar_year)): if (g_lunar_month_day[lunar_year - START_YEAR] & (1 << (iBit -1))): high = 30 else: high = 29 return (high, low) def lunar_year_days(year): days = 0 for i in range(1, 13): (high, low) = lunar_month_days(year, i) days += high days += low return days def get_ludar_date(tm): span_days = date_diff(tm) #阳历1901年2月19日为阴历1901年正月初一 #阳历1901年1月1日到2月19日共有49天 if (span_days <49): year = START_YEAR - 1 if (span_days <19): month = 11; day = 11 + span_days else: month = 12; day = span_days - 18 return (year, month, day) #下面从阴历1901年正月初一算起 span_days -= 49 year, month, day = START_YEAR, 1, 1 #计算年 tmp = lunar_year_days(year) while span_days >= tmp: span_days -= tmp year += 1 tmp = lunar_year_days(year) #计算月 (foo, tmp) = lunar_month_days(year, month) while span_days >= tmp: span_days -= tmp if (month == get_leap_month(year)): (tmp, foo) = lunar_month_days(year, month) if (span_days < tmp): return (0, 0, 0) span_days -= tmp month += 1 (foo, tmp) = lunar_month_days(year, month) #计算日 day += span_days return (year, month, day) #功能简单，只打印当月的 this_month()