zoukankan      html  css  js  c++  java
  • How can I supply an AntiForgeryToken when posting JSON data using $.ajax?

    How can I supply an AntiForgeryToken when posting JSON data using $.ajax?

    回答1

    You don't need the ValidationHttpRequestWrapper solution since MVC 4. According to this link.

    1. Put the token in the headers.
    2. Create a filter.
    3. Put the attribute on your method.

    Here is my solution:

    var token = $('input[name="__RequestVerificationToken"]').val();
    var headers = {};
    headers['__RequestVerificationToken'] = token;
    $.ajax({
        type: 'POST',
        url: '/MyTestMethod',
        contentType: 'application/json; charset=utf-8',
        headers: headers,
        data: JSON.stringify({
            Test: 'test'
        }),
        dataType: "json",
        success: function () {},
        error: function (xhr) {}
    });
    [AttributeUsage(AttributeTargets.Method | AttributeTargets.Class, AllowMultiple = false, Inherited = true)]
    public class ValidateJsonAntiForgeryTokenAttribute : FilterAttribute, IAuthorizationFilter
    {
        public void OnAuthorization(AuthorizationContext filterContext)
        {
            if (filterContext == null)
            {
                throw new ArgumentNullException("filterContext");
            }
    
            var httpContext = filterContext.HttpContext;
            var cookie = httpContext.Request.Cookies[AntiForgeryConfig.CookieName];
            AntiForgery.Validate(cookie != null ? cookie.Value : null, httpContext.Request.Headers["__RequestVerificationToken"]);
        }
    }
    
    
    [HttpPost]
    [AllowAnonymous]
    [ValidateJsonAntiForgeryToken]
    public async Task<JsonResult> MyTestMethod(string Test)
    {
        return Json(true);
    }

    回答2

    What is wrong is that the controller action that is supposed to handle this request and which is marked with the [ValidateAntiForgeryToken] expects a parameter called __RequestVerificationToken to be POSTed along with the request.

    There's no such parameter POSTed as you are using JSON.stringify(data) which converts your form to its JSON representation and so the exception is thrown.

    So I can see two possible solutions here:

    Number 1: Use x-www-form-urlencoded instead of JSON for sending your request parameters:

    data["__RequestVerificationToken"] = $('[name=__RequestVerificationToken]').val();
    data["fiscalyear"] = fiscalyear;
    // ... other data if necessary
    
    $.ajax({
        url: url,
        type: 'POST',
        context: document.body,
        data: data,
        success: function() { refresh(); }
    });

    Number 2: Separate the request into two parameters:

    data["fiscalyear"] = fiscalyear;
    // ... other data if necessary
    var token = $('[name=__RequestVerificationToken]').val();
    
    $.ajax({
        url: url,
        type: 'POST',
        context: document.body,
        data: { __RequestVerificationToken: token, jsonRequest: JSON.stringify(data) },
        success: function() { refresh(); }
    });

    So in all cases you need to POST the __RequestVerificationToken value.

  • 相关阅读:
    使用MySQL存储过程连续插入多条记录
    为什么编程语言以及数据库要从1970年1月1日开始计算时
    关于shtml页面include问题解决方案
    简单实用的FTP操作类
    js实现完美身份证号有效性验证
    .htaccess文件的建立和rewrite_module的启用
    php冒泡排序
    php实现汉诺塔问题(递归)
    简单的mysql数据库备份程序
    选择排序的php实现
  • 原文地址:https://www.cnblogs.com/chucklu/p/13713952.html
Copyright © 2011-2022 走看看