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  • HDU-2018多校7th-1011-Swordsman 附杜教fread代码

    HDU-6396

    题意:

       背景是打怪升级的故事,有k个不同属性的初始的能力值,每只怪物也有相同个数的能力值,你只能放倒k个能力值都比怪物大的,每放倒一个怪物,都可以得到相应的k个能力值。

    思路:

       根据k个能力值得到k个不同的排序,设立k个不同的指针从小到大开始移动,对满足被放倒的条件的属性进行标记,当某只monster的所有防御属性都被标记时,更新打怪者的能力值。

      这里的移动操作,可以通过判断cnt是否更新 来结束循环。而每次移动操作都使得指针跑到打怪者能力小于monster的位子。

      自己在练习的时候想的思路有点不周全,我们先对k个能力单独排序,单独给能放倒的怪兽打标记,最后看标记个数是否等于k个。反例是:对某种属性值,你只有打败了A号怪物,才能通过得到的能力值打败其他怪物,而在另一种属性下,A好怪物不能被放倒,但其他怪物能被放倒,这就造成了误判。

    代码:

    //#include<bits/stdc++.h>
    //#include<unordered_map>
    //#include<unordered_set>
    #include<functional>
    #include<algorithm>
    //#include<ext/rope>
    #include<iomanip>
    #include<climits>
    #include <iostream>
    #include<cstring>
    #include<cstdlib>
    #include<cstddef>
    #include<stdio.h>
    #include<memory>
    #include<vector>
    #include<cctype>
    #include<string>
    #include<cmath>
    #include<queue>
    #include<deque>
    #include<ctime>
    #include<stack>
    #include<map>
    #include<set>
    
    
    
    #define fi first
    #define se second
    #define pb push_back
    #define INF 0x3f3f3f3f
    #define pi 3.1415926535898
    #define lowbit(a)  (a&(-a))
    #define lson l,(l+r)/2,rt<<1
    #define rson (l+r)/2+1,r,rt<<1|1
    #define Min(a,b,c)  min(a,min(b,c))
    #define Max(a,b,c)  max(a,max(b,c))
    
    
    using namespace std;
    //using namespace __gnu_cxx;
    
    typedef long long ll;
    typedef pair<int,int> P;
    typedef unsigned long long ull;
    
    const ll LLMAX=2e18;
    const int MOD=1e9+7;
    const int MAXN=1e6+10;
    
    
    namespace IO{ 
        #define BUF_SIZE 100000 
        #define OUT_SIZE 100000 
        #define ll long long 
        //fread->read 
     
        bool IOerror=0; 
        inline char nc(){ 
            static char buf[BUF_SIZE],*p1=buf+BUF_SIZE,*pend=buf+BUF_SIZE; 
            if (p1==pend){ 
                p1=buf; pend=buf+fread(buf,1,BUF_SIZE,stdin); 
                if (pend==p1){IOerror=1;return -1;} 
                //{printf("IO error!
    ");system("pause");for (;;);exit(0);} 
            } 
            return *p1++; 
        } 
        inline bool blank(char ch){return ch==' '||ch=='
    '||ch=='
    '||ch=='	';} 
        inline void read(int &x){ 
            bool sign=0; char ch=nc(); x=0; 
            for (;blank(ch);ch=nc()); 
            if (IOerror)return; 
            if (ch=='-')sign=1,ch=nc(); 
            for (;ch>='0'&&ch<='9';ch=nc())x=x*10+ch-'0'; 
            if (sign)x=-x; 
        } 
        inline void read(ll &x){ 
            bool sign=0; char ch=nc(); x=0; 
            for (;blank(ch);ch=nc()); 
            if (IOerror)return; 
            if (ch=='-')sign=1,ch=nc(); 
            for (;ch>='0'&&ch<='9';ch=nc())x=x*10+ch-'0'; 
            if (sign)x=-x; 
        } 
        inline void read(double &x){ 
            bool sign=0; char ch=nc(); x=0; 
            for (;blank(ch);ch=nc()); 
            if (IOerror)return; 
            if (ch=='-')sign=1,ch=nc(); 
            for (;ch>='0'&&ch<='9';ch=nc())x=x*10+ch-'0'; 
            if (ch=='.'){ 
                double tmp=1; ch=nc(); 
                for (;ch>='0'&&ch<='9';ch=nc())tmp/=10.0,x+=tmp*(ch-'0'); 
            } 
            if (sign)x=-x; 
        } 
        inline void read(char *s){ 
            char ch=nc(); 
            for (;blank(ch);ch=nc()); 
            if (IOerror)return; 
            for (;!blank(ch)&&!IOerror;ch=nc())*s++=ch; 
            *s=0; 
        } 
        inline void read(char &c){ 
            for (c=nc();blank(c);c=nc()); 
            if (IOerror){c=-1;return;} 
        } 
        //fwrite->write 
        struct Ostream_fwrite{ 
            char *buf,*p1,*pend; 
            Ostream_fwrite(){buf=new char[BUF_SIZE];p1=buf;pend=buf+BUF_SIZE;} 
            void out(char ch){ 
                if (p1==pend){ 
                    fwrite(buf,1,BUF_SIZE,stdout);p1=buf; 
                } 
                *p1++=ch; 
            } 
            void print(int x){ 
                static char s[15],*s1;s1=s; 
                if (!x)*s1++='0';if (x<0)out('-'),x=-x; 
                while(x)*s1++=x%10+'0',x/=10; 
                while(s1--!=s)out(*s1); 
            } 
            void println(int x){ 
                static char s[15],*s1;s1=s; 
                if (!x)*s1++='0';if (x<0)out('-'),x=-x; 
                while(x)*s1++=x%10+'0',x/=10; 
                while(s1--!=s)out(*s1); out('
    '); 
            } 
            void print(ll x){ 
                static char s[25],*s1;s1=s; 
                if (!x)*s1++='0';if (x<0)out('-'),x=-x; 
                while(x)*s1++=x%10+'0',x/=10; 
                while(s1--!=s)out(*s1); 
            } 
            void println(ll x){ 
                static char s[25],*s1;s1=s; 
                if (!x)*s1++='0';if (x<0)out('-'),x=-x; 
                while(x)*s1++=x%10+'0',x/=10; 
                while(s1--!=s)out(*s1); out('
    '); 
            } 
            void print(double x,int y){ 
                static ll mul[]={1,10,100,1000,10000,100000,1000000,10000000,100000000, 
                    1000000000,10000000000LL,100000000000LL,1000000000000LL,10000000000000LL, 
                    100000000000000LL,1000000000000000LL,10000000000000000LL,100000000000000000LL}; 
                if (x<-1e-12)out('-'),x=-x;x*=mul[y]; 
                ll x1=(ll)floor(x); if (x-floor(x)>=0.5)++x1; 
                ll x2=x1/mul[y],x3=x1-x2*mul[y]; print(x2); 
                if (y>0){out('.'); for (size_t i=1;i<y&&x3*mul[i]<mul[y];out('0'),++i); print(x3);} 
            } 
            void println(double x,int y){print(x,y);out('
    ');} 
            void print(char *s){while (*s)out(*s++);} 
            void println(char *s){while (*s)out(*s++);out('
    ');} 
            void flush(){if (p1!=buf){fwrite(buf,1,p1-buf,stdout);p1=buf;}} 
            ~Ostream_fwrite(){flush();} 
        }Ostream; 
        inline void print(int x){Ostream.print(x);} 
        inline void println(int x){Ostream.println(x);} 
        inline void print(char x){Ostream.out(x);} 
        inline void println(char x){Ostream.out(x);Ostream.out('
    ');} 
        inline void print(ll x){Ostream.print(x);} 
        inline void println(ll x){Ostream.println(x);} 
        inline void print(double x,int y){Ostream.print(x,y);} 
        inline void println(double x,int y){Ostream.println(x,y);} 
        inline void print(char *s){Ostream.print(s);} 
        inline void println(char *s){Ostream.println(s);} 
        inline void println(){Ostream.out('
    ');} 
        inline void flush(){Ostream.flush();}
        #undef ll 
        #undef OUT_SIZE 
        #undef BUF_SIZE 
    };
    using namespace IO;
    template<class T>
    inline void read(T &DataIn)
    {
        DataIn=0;    T Flag=0;   char c=getchar();
        while(!isdigit(c)){ Flag|=c=='-'; c=getchar(); }
        while(isdigit(c)){ DataIn=DataIn*10+c-'0'; c=getchar(); }
        DataIn= Flag? -DataIn: DataIn;
    }
    
    template<class T>
    inline void write(T DataOut,char EndChar='
    ')
    {
        T lenth=0,number[30];
        if(DataOut==0){ putchar(48); return; }
        while(DataOut>0){ number[++lenth]=DataOut%10; DataOut/=10;}
        for(int i=lenth;i>=1;i--)    putchar(number[i]+48);
        putchar(EndChar);
    }
    
    int a[10],pos[10];
    struct node{
        ll hit[10],exp[10],id;
    }b[MAXN];
    
    int p[10][MAXN];
    inline bool cmp1(int x,int y){
        return b[x].hit[0]<b[y].hit[0];
    }
    
    inline bool cmp2(int x,int y){
        return b[x].hit[1]<b[y].hit[1];
    }
    
    inline bool cmp3(int x,int y){
        return b[x].hit[2]<b[y].hit[2];
    }
    
    inline bool cmp4(int x,int y){
        return b[x].hit[3]<b[y].hit[3];
    }
    
    inline bool cmp5(int x,int y){
        return b[x].hit[4]<b[y].hit[4];
    }
    
    
    int vis[MAXN];
    int main()
    {
        
        int T;  cin>>T;
        while(T--){
            int n,k,cnt=0;
            read(n);read(k);
            //scanf("%d%d",&n,&k);
            for(int i=0;i<k;i++)  read(a[i]);
            for(int i=0;i<n;i++){
    
                vis[i] = 0;
                b[i].id=i;
                for(int j=0;j<k;j++)
                    read(b[i].hit[j]),p[j][i] = i;;
                for(int j=0;j<k;j++)
                    read(b[i].exp[j]);
    
            }
            pos[0] = pos[1] = pos[2] =pos[3] = pos[4] = 0;
            for(int i=0; i<k; i++){
                
                if(i==0) sort(p[0],p[0]+n,cmp1);
                else if(i==1) sort(p[1],p[1]+n,cmp2);
                else if(i==2) sort(p[2],p[2]+n,cmp3);
                else if(i==3) sort(p[3],p[3]+n,cmp4);
                else if(i==4) sort(p[4],p[4]+n,cmp5);
            }
    
            while(true){
                    int c = cnt;
                    for(int i=0; i<k; i++){
                        while(pos[i] < n && b[p[i][pos[i]]].hit[i] <= a[i]){
                            int id =  p[i][pos[i]];
                            vis[id]++;
                            if(vis[id] == k){
                                cnt++;
                                for(int j=0; j<k; j++){
                                    a[j] += b[id].exp[j];
                                }
                            }
                            pos[i]++;
                        }
                    }
                    if(cnt==c){
                        break;
                    }
            }
    
            //write(cnt);
            IO::println(cnt);
            for(int i=0;i<k;i++)
                IO::print(a[i]),IO::print(i!=k-1?' ':'
    ');
    
        }
        return 0;
    }
    FREAD in here
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  • 原文地址:https://www.cnblogs.com/ckxkexing/p/9474167.html
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