Decimal
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 103 Accepted Submission(s): 49
Problem Description
Given a positive integer n, determine if 1n is an infinite decimal in decimal base. If the answer is yes, print “Yes” in a single line, or print “No” if the answer is no.
Input
The first line contains one positive integer T (1 ≤ T ≤ 100), denoting the number of test cases.
For each test case:
Input a single line containing a positive integer n (1 ≤ n ≤ 100).
For each test case:
Input a single line containing a positive integer n (1 ≤ n ≤ 100).
Output
Output T lines each contains a string “Yes” or “No”, denoting the answer to corresponding test case.
Sample Input
2
5
3
Sample Output
No
Yes
Hint
1/5 = 0.2, which is a finite decimal.
1/3 = 0.333 · · · , which is an infinite decimal.
Source
题解:
问1/n是否是有限小数,队友很快反应过来找n是否含有非2和非5的因子。
参考代码:
#include<bits/stdc++.h> using namespace std; int main() { int t; scanf("%d",&t); while(t--) { int n; scanf("%d",&n); if(n%5==0) { do{ n/=5; }while(n%5==0); } if(n%2==0) { do{n/=2;}while(n%2==0); } if(n==1) puts("No"); else puts("Yes"); } return 0; }