zoukankan      html  css  js  c++  java
  • Mathematica新特性Inactive, 求解复杂微分方程

    Inactive阻止函数的计算, 求解微分方程有奇效

    Block[{Integrate = Inactive[Integrate]}, 
     DSolve[((H - h0)^(7/5) P0 (T - c t0))/(T0 (H - h0 - m*h[t])^(7/5)) + 
        1/2 [Rho]*(h'[
            t] - (h[t] m (m [Pi] r^2 - S2))/(2 (H - h0 + 
                h[t] m) [Pi] r^2) + (h[
               t] m^2 (2 H [Pi] r^2 - 2 h0 [Pi] r^2 + h[t] m*[Pi]*r^2 -
                 h[t]*S2 - 
                2 H*S2))/(2 (H - h0 + 
                 h[t] m)^2 [Pi] r^2) - (m (2 H [Pi] r^2 - 
                 2 h0 [Pi] r^2 + h[t] m [Pi] r^2 - h[t] S2 - 
                 2 H S2))/(2 (H - h0 + h[t] m) [Pi] r^2)*h'[t]) == 
       P0 + g [Rho] (h[t] + 
           h0 - (h[t] m (2 H [Pi] r^2 - 2 h0 [Pi] r^2 + 
                h[t] m [Pi] r^2 - h[t] S2 - 2 H S2))/(2 (H - h0 + 
                h[t] m) [Pi] r^2) - m*h[t]) + 
        1/2 [Rho] Derivative[1][h][t]^2, h[t], t]]
    

      

  • 相关阅读:
    1059 C语言竞赛
    1058 选择题
    1057 数零壹
    1056 组合数的和
    1055 集体照
    Mysql--分库分表
    Mysql--改表结构
    Mysql--开始阶段
    Mysql--常用语句
    Mysql--grant授权
  • 原文地址:https://www.cnblogs.com/dabaopku/p/6423840.html
Copyright © 2011-2022 走看看