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  • Interesting Computer Game

    Interesting Computer Game

    #include <iostream>
    #include <vector>
    #include <algorithm>
    #include <string>
    #include <set>
    #include <queue>
    #include <map>
    #include <sstream>
    #include <cstdio>
    #include <cstring>
    #include <numeric>
    #include <cmath>
    #include <iomanip>
    #include <deque>
    #include <bitset>
    #include <cassert>
    //#include <unordered_set>
    #include <unordered_map>
    #define ll              long long
    #define pii             pair<int, int>
    #define rep(i,a,b)      for(int  i=a;i<=b;i++)
    #define dec(i,a,b)      for(int  i=a;i>=b;i--)
    #define forn(i, n)      for(int i = 0; i < int(n); i++)
    using namespace std;
    int dir[4][2] = { { 1,0 },{ 0,1 } ,{ 0,-1 },{ -1,0 } };
    const long long INF = 0x7f7f7f7f7f7f7f7f;
    const int inf = 0x3f3f3f3f;
    const double pi = acos(-1.0);
    const double eps = 1e-6;
    const int mod = 1e9 + 7;
    
    inline ll read()
    {
        ll x = 0; bool f = true; char c = getchar();
        while (c < '0' || c > '9') { if (c == '-') f = false; c = getchar(); }
        while (c >= '0' && c <= '9') x = (x << 1) + (x << 3) + (c ^ 48), c = getchar();
        return f ? x : -x;
    }
    inline ll gcd(ll m, ll n)
    {
        return n == 0 ? m : gcd(n, m % n);
    }
    void exgcd(ll A, ll B, ll& x, ll& y)
    {
        if (B) exgcd(B, A % B, y, x), y -= A / B * x; else x = 1, y = 0;
    }
    inline int qpow(int x, ll n) {
        int r = 1;
        while (n > 0) {
            if (n & 1) r = 1ll * r * x % mod;
            n >>= 1; x = 1ll * x * x % mod;
        }
        return r;
    }
    inline int inv(int x) {
        return qpow(x, mod - 2);
    }
    ll lcm(ll a, ll b)
    {
        return a * b / gcd(a, b);
    }
    /**********************************************************/
    const int N = 1e5 + 5;
    
    unordered_map<int, int> f, vis,p,cntdot;
    int find(int x) {
        return f[x] == x ? x : f[x] = find(f[x]);
    }
    bool add(int x, int y) {
        int fx = find(x), fy = find(y);
        if (fx != fy) {
            f[fx] = fy;
            return true;
        }
        return false;
    }
    
    int cnt, fg, sz;
    
    int a[N], b[N],c[N];
    int main() {
        //ios::sync_with_stdio(false);cin.tie(0); cout.tie(0);
        int T;
        scanf("%d", &T);
        int cntt = 1;
        while (T--)
        {
            memset(c, 0, sizeof(c));
            vis.clear();
            f.clear();
            cntdot.clear();
            p.clear();
            int res = 0;
            cnt = 0;
            int n;
            scanf("%d", &n);
            rep(i, 1, n)
            {
                scanf("%d%d", &a[i], &b[i]);
                f[a[i]] = a[i];
                f[b[i]] = b[i];
            }
            int cntg = 0, cntn = 0, len = 1;
            unordered_map<int, int> mmp;
            rep(i, 1, n)
            {
                if (find(a[i]) == find(b[i]))
                    c[len++] = find(a[i]);
                else
                    add(a[i], b[i]);
            }
            rep(i, 1, len)
                p[find(c[i])] = 1;
            rep(i, 1, n)
            {
                if (!vis[a[i]])
                    cntdot[find(a[i])]++;
                vis[a[i]] = 1;
                if (!vis[b[i]])
                    cntdot[find(b[i])]++;
                vis[b[i]] = 1;
            }
            for (auto x : cntdot)
            {
                if (!p[x.first])
                    res--;
                res += x.second;
            }
            printf("Case #%d: %d
    ", cntt++,res);
        }
    }
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  • 原文地址:https://www.cnblogs.com/dealer/p/13432012.html
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