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  • LeetCode_492. Construct the Rectangle

    492. Construct the Rectangle

    Easy

    For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

    1. The area of the rectangular web page you designed must equal to the given target area.
    
    2. The width W should not be larger than the length L, which means L >= W.
    3. The difference between length L and width W should be as small as possible.
    You need to output the length L and the width W of the web page you designed in sequence.

    Example:

    Input: 4
    Output: [2, 2]
    Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
    But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.
    

    Note:

    1. The given area won't exceed 10,000,000 and is a positive integer
    2. The web page's width and length you designed must be positive integers.
    package leetcode.easy;
    
    public class ConstructTheRectangle {
    	private static void print_arr(int[] nums) {
    		for (int num : nums) {
    			System.out.print(num + " ");
    		}
    		System.out.println();
    	}
    
    	public int[] constructRectangle(int area) {
    		int[] arr = new int[2];
    		for (int i = (int) Math.sqrt(area); i >= 1; i--) {
    			if (area % i == 0) {
    				arr[0] = area / i;
    				arr[1] = i;
    				break;
    			}
    		}
    		return arr;
    	}
    
    	@org.junit.Test
    	public void test() {
    		print_arr(constructRectangle(4));
    	}
    }
    
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  • 原文地址:https://www.cnblogs.com/denggelin/p/12110473.html
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