zoukankan      html  css  js  c++  java
  • 生成字典小技巧

    # 将list3 这种数据类型转化成list4类型
    list3 = [
    {"name": "a", "hobby": "抽烟"},
    {"name": "a", "hobby": "喝酒"},
    {"name": "a", "hobby": "烫头"},
    {"name": "a", "hobby": "Massage"},
    {"name": "b", "hobby": "喊麦"},
    {"name": "b", "hobby": "街舞"},
    {"name": "b", "hobby": "出差"},
    ]
    list4 = [
    {"name": "a", "hobby_list": ["抽烟", "喝酒", "烫头", "Massage"]},
    {"name": "b", "hobby_list": ["喊麦", "街舞","出差"]},
    ]
    1.
    # dic={}
    # for i in list3:
    # if i["name"] in dic:
    # dic[i["name"]]["hobby_list"].append(i["hobby"])
    # else:
    # dic[i['name']] = {'name': i['name'], 'hobby_list': [i['hobby'], ]}
    # print(list(dic.values()))
    1.1
    # dic = {}
    # for i in list3:
    # if i['name'] not in dic:
    # dic[i['name']] = {'name': i['name'],'hobby_list':[i['hobby'],]}
    # else:
    # dic[i['name']]['hobby_list'].append(i['hobby'])
    # print(list(dic.values()))
    2.
    # l1=[]
    # for i in list3:
    # for j in l1:
    # if i['name'] == j['name']:
    # j['hobby_list'].append(i['hobby'])
    # break
    # else:
    # l1.append({'name': i['name'], 'hobby_list':[i['hobby'],]})
    # print(l1)

    3.
    # li=[]
    # lis=[]
    # dic={"name":"","hobby_list":[]}
    # for i in range(len(list3)):
    # li.append(list3[i]["name"])
    # li=list(set(li))
    # print(li)
    # for i in li:
    # dic={}
    # dic["name"]=i
    # dic["hobby_list"]=[]
    # for k in range(len(list3)):
    # if i==list3[k]["name"]:
    # dic["hobby_list"].append(list3[k]["hobby"])
    # lis.append(dic)
    # print(lis)
  • 相关阅读:
    HDOJ2553 N皇后问题
    NYOJ284 坦克大战 BFS/优先队列
    NYOJ14 会场安排问题 贪心
    POJ1664 放苹果
    NYOJ119 士兵杀敌(三) RMQ
    POJ3264 Balanced Lineup RMQ/线段树
    POJ1127 Jack Straws
    HDOJ1128 Self Numbers
    水晶报表CrystalReports很强大也很简单!
    PetShop项目学习笔记(三)
  • 原文地址:https://www.cnblogs.com/diracy/p/13123825.html
Copyright © 2011-2022 走看看