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  • [poj1273]Drainage Ditches(最大流)

    解题关键:最大流裸题

    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<cstdlib>
    #include<cmath>
    #include<iostream>
    #include<queue>
    #include<vector>
    #define inf 0x3f3f3f3f
    #define MAX_V 252
    using namespace std;
    typedef long long ll;
    struct edge{int to,cap,rev;};//终点,容量,反向边
    vector<edge>G[MAX_V];
    int level[MAX_V],iter[MAX_V];
    int n,m,s,t;
    void add_edge(int from,int to,int cap){
        G[from].push_back((edge){to,cap,(int)G[to].size()});
        G[to].push_back((edge){from,0,(int)G[from].size()-1});
    }
    void bfs(int s){
        memset(level,-1,sizeof level);
        queue<int>que;
        level[s]=0;
        que.push(s);
        while(!que.empty()){
            int v=que.front();que.pop();
            for(int i=0;i<G[v].size();i++){
                edge &e=G[v][i];
                if(e.cap>0&&level[e.to]<0){
                    level[e.to]=level[v]+1;
                    que.push(e.to);
                }
            }
        }
    }
    
    int dfs(int v,int t,int f){
        if(v==t) return f;
        for(int &i=iter[v];i<G[v].size();i++){
            edge &e=G[v][i];
            if(e.cap>0&&level[v]<level[e.to]){
                int d=dfs(e.to,t,min(f,e.cap));
                if(d>0){
                    e.cap-=d;
                    G[e.to][e.rev].cap+=d;
                    return d;
                }
            }
        }
        return 0;
    }
    
    int dicnic(int s,int t){
        int flow=0,f;
        while(1){
            bfs(s);
            if(level[t]<0) return flow;
            memset(iter,0,sizeof iter);
            while((f=dfs(s,t,inf))>0){
                flow+=f;
            }
        }
        return flow;
    }
    
    int main(){
        int u,v,f;
        while(scanf("%d%d",&m,&n)!=EOF){
            memset(G,0,sizeof G);
            for(int i=0;i<m;i++){
                scanf("%d%d%d",&u,&v,&f);
                add_edge(u,v,f);
            }
            s=1,t=n;
            int ans=dicnic(s,t);
            printf("%d
    ",ans);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/elpsycongroo/p/7888370.html
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