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  • 四则运算

    import random

    from fractions import Fraction

    def newint():
    opr = ['+', '-', '×', '÷']
    fh = random.randint(0, 3)
    n1 = random.randint(1, 20)
    n2 = random.randint(1, 20)
    rjg = 0
    if fh == 0:
    rjg = n1 + n2
    elif fh == 1:
    n1, n2 = max(n1, n2), min(n1, n2)
    rjg = n1 - n2
    elif fh == 2:
    rjg = n1 * n2
    elif fh == 3:
    n1, n2 = max(n1, n2), min(n1, n2)
    while n1 % n2 != 0:
    n1 = random.randint(1, 10)
    n2 = random.randint(1, 10)
    n1, n2 = max(n1, n2), min(n1, n2)
    rjg = int(n1 / n2)
    print(n1, opr[fh], n2, '= ', end='')
    return rjg


    def newfra():
    opr = ['+', '-', '×', '÷']
    fh = random.randint(0, 3)
    t1 = random.randint(1, 10)
    t2 = random.randint(t1, 10)
    n1 = Fraction(t1, t2)
    t1 = random.randint(1, 10)
    t2 = random.randint(t1, 10)
    n2 = Fraction(t1, t2)
    rjg = 0
    if fh == 0:
    rjg = n1 + n2
    elif fh == 1:
    n1, n2 = max(n1, n2), min(n1, n2)
    rjg = n1 - n2
    elif fh == 2:
    rjg = n1 * n2
    elif fh == 3:
    n1, n2 = max(n1, n2), min(n1, n2)
    rjg = n1 / n2
    print(n1, opr[fh], n2, '= ', end='')
    return rjg

    def newtest():
    opr = ['+', '-', '×', '÷']
    print('输入题库所需要的题目数量')
    n=int(input())
    rjg=[]
    m=0
    while m<=(n-1):
    fh = random.randint(0, 4)
    if fh==0:
    print(m+1,end='、')
    rjg.append(newfra())
    print(' ')
    else:
    print(m+1,end='、')
    rjg.append(newint())
    print(' ')
    m=m+1
    m=0
    print('答案:')
    while m<=(n-1):
    print(m+1,'、',rjg[m])
    m=m+1



    print('1、四则运算')
    print('2、制作题库')
    n=int(input())
    if n==1:
    print('input "0000" to Quit')
    while True:
    fh = random.randint(0, 4)
    if fh == 0:
    rjg = newfra()
    jg = input()
    if jg == '0000':
    break;
    sr = Fraction(jg)
    if sr == rjg:
    print('right')
    else:
    print('error. the Tight answer is', rjg)
    else:
    rjg = newint()
    jg = input()
    if jg == '0000':
    break;
    sr = int(jg)
    if sr == rjg:
    print('right')
    else:
    print('error. the Tight answer is', rjg)
    if n==2:
    newtest()

    参考:https://blog.csdn.net/weixin_30539835/article/details/99789504

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  • 原文地址:https://www.cnblogs.com/gong-jie/p/14056314.html
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